Question

SOMEONE HELP ASAPPPPPPPPP

Answer 1

Answer:

D = $f^{-1}(x) = 4(x+12)$ = $f^{-1}(x) = 4x+48$

Step-by-step explanation:

First, replace f(x) with y, and switch x and y:

$y = \frac{1}{4}x-12$

$x = \frac{1}{4}y-12$

Now, solve for y again:

$x+12=\frac{1}{4}y$

$y = 4(x+12)$

Replace y with correct inverse function notation, and you have your answer:

$f^{-1}(x) = 4(x+12)$

Answer 2

h(x)= 48x+8 is your answer then dude