9 more than y is an expression so it would be 9+y
Answer:
the answer is x >0 hope this helped
This sequence has generating function

(if we include
for a moment)
Recall that for
, we have

Take the derivative to get


Take the derivative again:


Take the derivative one more time:


so we have

543,100.....543,200......543,300
Answer:
Cual es el valor de F (2) translates to "What is the value of F (2)"
Hope this helped.