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3 years ago

8

F (x)=2x+1 and g (x)=x^2-7, find (f/g)(x)

2 answers:

Andrej [43]3 years ago

5 0

(f/g)(x) just means f(x)/g(x)

So the answer is (2x+1)/(x^2-7)

Ede4ka [16]3 years ago

3 0

Answer:

The value of (f/g)(x) is:

$\dfrac{2x+1}{x^2-7}$

Step-by-step explanation:

f (x)=2x+1 and g (x)=x²-7

$(\dfrac{f}{g})(x)= \dfrac{f(x)}{g(x)}$

⇒ $(\dfrac{f}{g})(x)=\dfrac{2x+1}{x^2-7}$

Hence, the value of (f/g)(x) is:

$\dfrac{2x+1}{x^2-7}$

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Sholpan [36]

I'm guessing on the make up of the matrices.
First off let's look at [C][F].
[C]=
[F]=
[C][F]=
where each element of [C][F] comes from multiplying a row of [C] with a column of [F].
Example: First element is product of first row and first column.

.
.
.
Now that we have [C][F], we can subtract it from [B], element by element,

[B]-[C][F]=
[B]-[C][F]=
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If this is not how the matrices look,please re-state the problem and be more specific about the make up of the matrices (rows x columns).
Here's an example.
[A] is a 2x2 matrix. A=[1,2,3,4].
The assumption is that [A] looks like this,
[A]=
[B] is a 3x2 matrix. B=[5,6,7,8,9,10]
[B]=

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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

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Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

3 years ago

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