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Over [174]
3 years ago
5

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

up right

Mathematics
1 answer:
lesya [120]3 years ago
6 0

Answer:


Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

a_{n}=a_{n-1}*r

so comparing it with the given recursive formula a_{n}=a_{n-1}*-4

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.

Explicit Formula =-2*(-4)^{n-1}

2) Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.

Explicit Formula =-4*(-2)^{n-1}

3)Comparing the given recursive formula a_{n}=a_{n-1}*3

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =3

8th term= a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.

Explicit Formula =-1*(3)^{n-1}

4)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.

Explicit Formula =3*(-4)^{n-1}

5)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.

Explicit Formula =-4*(-4)^{n-1}

6)Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.

Explicit Formula =3*(-2)^{n-1}

7)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.

Explicit Formula =4*(-5)^{n-1}

8)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.

Explicit Formula =2*(-5)^{n-1}

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