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Marta_Voda [28]
3 years ago
13

The circumference of a circle that has a radius of 7cm. use 3.14. for pie

Mathematics
1 answer:
sveta [45]3 years ago
7 0

https://www.google.com/imgres?imgurl=http://pad2.whstatic.com/images/thumb/0/0b/Calculate-the-Circum...
 this link will give u an example how to find it with the formula



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Step-by-step explanation:

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You are 10 years old and have $500 to put in the bank to save for college. You will earn 5% simple interest rate. If you leave i
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$814.48

Step-by-step explanation:

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Read 2 more answers
Given the points (2,k) (2,k) and (0,−6) (0,−6) , for which values of k would the distance between the points be 5 – √ 5
11Alexandr11 [23.1K]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have:

(2,\ k)\to x_1=2,\ y_1=k\\(0,\ -6)\to x_2=0,\ y_2=-6\\d=5-\sqrt5

Substitute:

\sqrt{(0-2)^2+(-6-k)^2}=5-\sqrt5\\\\\sqrt{(-2)^2+[-(6+k)]^2}=5-\sqrt5\\\\\sqrt{4+(6+k)^2}=5-\sqrt5\ \ \ \ \ |^2\\\\4+(6+k)^2=(5-\sqrt5)^2\ \ \ \ |use\ (a-b)^2=a^2-2ab+b^2

4+(6+k)^2=5^2-2\cdot5\cdot\sqrt5+(\sqrt5)^2\\\\4+(6+k)^2=25-10\sqrt5+5\ \ \ \ |-4\\\\(6+k)^2=26-10\sqrt5\to6+k=\pm\sqrt{26-10\sqrt5}\ \ \ \ |-6\\\\\boxed{k=-6-\sqrt{26-10\sqrt5}\ \vee\ k=-6+\sqrt{26-10\sqrt5}}

If d=\sqrt5, then:

\sqrt{4+(6+k)^2}=\sqrt5\ \ \ \ |^2\\\\(\sqrt{4+(6+k)^2})^2=(\sqrt5)^2\\\\4+(6+k)^2=5\ \ \ \ |-4\\\\(6+k)^2=1\to 6+k=\pm\sqrt1\\\\6+k=\pm1\ \ \ \ |-6\\\\\boxed{k=-7\ \vee\ k=-5}

3 0
3 years ago
SOMEONE HELP ME PLS I DONT UNDERSTAND AND GIVE ONE OF THE SELECTED OPTIONS PLS :)
VLD [36.1K]
X = 130°

they are alternate exterior angles. the one you have highlighted is correct.
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3 years ago
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