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3 years ago

Look at this system of equations. How can the system be changed so that the two equations have equal x-coefficients?

1 answer:

Volgvan3 years ago

5 0

I believe the correct answer from the choices listed above is option A. The <span>system can be changed so that the two equations have equal x-coefficients by multiplying </span><span>both sides of the top equation by 2 resulting to 6x + 4y = 24. Hope this answers the question.</span>

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SOMEONE PLEASE HELP 100 POINTS AND BRAINLIEST AND 5 STAR RATING! PLEASE HELP! :)

weqwewe [10]

1 cm 3 cm

--------- = ---------

3 in x inches

The ratio has to stay in the same order cm on top, inches on the bottom

Choice C

4 0

3 years ago

You have a bag of marbles. 4 are blue, 3 are red, 2 are green, 2 are yellow are 4 are purple. What is the probability that you p

valkas [14]

Answer:

2/35

Step-by-step explanation:

There are 15 marbles in total.

$\frac{4\\}{15}$ × $\frac{3}{14}$

The answer would be $\frac{2}{35}$ .

6 0

3 years ago

Read 2 more answers

The formula to determine energy is uppercase E = one-half m v squared. What is the formula solved for v?

alexandr402 [8]

Answer:

Step-by-step explanation:

$E=\frac{1}{2}mv^2$

All the variables on the right are being multiplied together then the whole mess is being divided by 2. Let's get rid of the 2 first. The undoing of division is multiplication, so we will begin by multiplying both sides by 2 to get

$2E=mv^2$

Next we will move the m. The undoing of multiplication is division. So we divide both sides by m to get

$\frac{2E}{m}=v^2$

The undoing of a square is to take the square root, so we will do that to both sides giving us, finally

$\sqrt{\frac{2E}{m} }=v$

6 0

3 years ago

Read 2 more answers

Please help me:

lora16 [44]

Answer:

6 units

Step-by-step explanation:

This coordinate is a three dimensional coordinate, which involves positive and negative x,y, and z axis.

The y axis is from left to right, i.e from negative to positive.

So 6 unit left is = -6 but it explains moving left .

Thank you

6 0

3 years ago

Suppose an object is launched from ground level directly upward at 57.4 f/s Write a function to represent the object’s height ov

Semmy [17]

Answer: p(t) = (-16 ft/s^2)*t^2 + (57.4 ft/s)*t

Step-by-step explanation:

We can suppose that the only force acting on the object is the gravitational force, then the acceleration of the object will be equal to the gravitational acceleration.

Then we can write:

a(t) = -32 ft/s^2

Where the negative sign is because this acceleration is downwards.

Now, to get the vertical velocity of the object, we need to integrate over time to get:

v(t) = (-32 ft/s^2)*t + v0

where t represents time in seconds and v0 is the constant of integration, and in this case, is the initial vertical velocity.

In this case, the initial velocity is 57.4 ft/s upwards, then the velocity equation is:

v(t) = (-32 ft/s^2)*t + 57.4 ft/s

To get the position equation we need to integrate over time again, to get:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (57.4 ft/s)*t + p0

Where p0 is the initial height of the object, as it was launched from the ground, then the initial position is p0 = 0ft.

then the position equation (that is the function that represents the height of the object as a function over time) is:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (57.4 ft/s)*t

p(t) = (-16 ft/s^2)*t^2 + (57.4 ft/s)*t

3 0

3 years ago