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Reil [10]
3 years ago
10

3y + 15x = - 15

Mathematics
1 answer:
jasenka [17]3 years ago
7 0

Answer:

b

Step-by-step explanation:

Given

3y + 15x = - 15

Isolate 3y by subtracting 15x from both sides

3y = - 15x - 15 ( divide all terms by 3 )

y = - 5x - 5 → b

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NEED SMART STUDENT PLEASEE​
marshall27 [118]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

All triangles equal up to 180⁰. With that in mind, let's solve

Step-by-step explanation:

<em>x</em> + 124⁰ + 33⁰ = 180⁰

    \_______/

<em>x</em>    +   157⁰      = 180⁰

      -   157⁰         -157⁰

    _______   ______

<em>x</em>                      =   23⁰

<em>x</em> = 23⁰

The bolded part is your answer. I hope this helps!

5 0
4 years ago
Read 2 more answers
Please help, graph the line
aleksandrvk [35]

Answer:

Step-by-step explanation:

15) x should +ve

16) x should be -ve

4 0
2 years ago
Graph the following inequality 6x+y&gt;-6
Rudiy27
1738

u know how im rocking....
5 0
4 years ago
A. 12
kondor19780726 [428]

Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The  student is 6 feet tall. What is the height of the tree? Show all work

<em><u>Answer:</u></em>

Option D

The height of tree is 20 feet tall

<em><u>Solution:</u></em>

From given question,

Shadow of tree = 30 feet

Height of tree = ?

Height of student = 6 feet

Shadow of student = 9 feet

We have to find the height of tree

We can solve the sum by proportion

\frac{\text{height of tree}}{\text{shadow of tree}} = \frac{\text{height of student}}{\text{shadow of tree}}

This forms a proportion and we can solve the sum by cross multiplying

\frac{\text{height of tree}}{30} = \frac{6}{9}\\\\\text{height of tree} = 30 \times \frac{6}{9} = 30 \times \frac{2}{3}\\\\\text{ height of tree } = 10 \times 2 = 20

Thus height of tree is 20 feet tall

5 0
3 years ago
-12x divided by -4= -27 what does x equal
Ede4ka [16]
X=9   -12 divided by -4 is -3, so you get -3x=-27. When you divide -27 by -3 you get positive 9. Thus making X=9
7 0
4 years ago
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