Answers and workings in the attachment below.
Given:
The scale of a map is 
.
The distance between two buildings is 60 miles.
To find:
The distance between the given building on the map.
Solution:
We have,
It means, 80 miles in real life = 
on the map.
1 mile in real life = 
on the map.
60 mile in real life = 
on the map.
= 
on the map.
= 
on the map.
Therefore, the buildings are apart on the map.
Answer:
4/5
Step-by-step explanation:
0.8 (to a fraction) 8/10
8/2=4
10/2=5
4/5
Answer:
See below
Step-by-step explanation:
<u>Parent function:</u>
<u>Transformed function:</u>
- y = 4(3)⁻²ˣ⁺⁸ + 6, (note. I see this as 8, sorry if different but it doesn't make any change to transformation method)
<u>Transformations to be applied:</u>
- f(x) → f(-x) reflection over y-axis
- f(-x) → f(-2x) stretch horizontally by a factor of 2
- f(-2x) → f(-2x + 8) translate 8 units right
- f(-2x + 8) → 4f(-2x + 8) stretch vertically by a factor of 4
- 4f(-2x + 8) → 4f(-2x + 8) + 6 translate 6 units up
circurference of gear = 2πr
= 2π(10)
= 62.83185307 inches
= 62.83 inches (4sf)
