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Stels [109]
3 years ago
6

What is the discriminant of the quadratic equation 0 = –x2 + 4x – 2?

Mathematics
1 answer:
daser333 [38]3 years ago
3 0
√8 is the discriminant
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The brand xyz dog food costs $36 for 15 pounds of dog food. What is the cost per pound?
HACTEHA [7]

Answer:

Step-by-step explanation:

36/$15 = $2.04 per pound

3 0
3 years ago
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Are these two functions or no? i name brainiest
snow_tiger [21]

Answer:

these two isn't a function

Step-by-step explanation:

On the table you can see that the ratio isn't equivalent

On the chart you can see that one domain has two ranges which also tells us that this two isn't a function

3 0
3 years ago
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Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
the length of AB_ is 9 cm a dilation with a scale factor of 2 is applied to AB_ what is the length of the image of AB after the
Minchanka [31]

The scale factor of two means you need to multiply the original length by 2:

9 x 2 = 18

The new length would be 18 cm.

6 0
3 years ago
Really need this todayyyyyy
Bond [772]

Answer:

Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i

Step-by-step explanation:

x^{2} - 4x + 5 =0

( 4± \sqrt{16 - 4*1*5} ) / 2 = (

x1= 2+i

x2= 2-i

2x^{2} +6x + 5 =0

( -6 ± \sqrt{36 - 4*2*5} ) / 4 = (-6 ± \sqrt{-4} )/4= (-3 ± i)/2

x1 = -3/2 +i

x2 = -3/2 -i

7 0
3 years ago
Read 2 more answers
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