In a population that is normally distributed that has a mean of 45 with a standard
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Answers:
P(A) = 7/12
P(B) = 1/4
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Explanation:
Instead of having one die, let's say we have two dice. I'll make one red and the other blue.
I'll be using the dice chart shown below. The red and blue values add up to the black numbers inside the table. For instance, we have 1+1 = 2 in the upper left corner. There are 6*6 = 36 sums total.
Using that table, we can see the following:
- There are 6 copies of "7"
- There are 5 copies of "8"
- There are 4 copies of "9"
- There are 3 copies of "10"
- There are 2 copies of "11"
- There is 1 copy of "12"
In total, we have 6+5+4+3+2+1 = 21 instances where the two dice add to something larger than 6.
This is out of 36 ways to roll two dice.
Therefore P(A) = 21/36 = (3*7)/(3*12) = 7/12
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If a number is divisible by 4, then it is a multiple of 4.
The multiples of 4 found in the table are: 4, 8, 12
We have
- 3 copies of "4"
- 5 copies of "8"
- 1 copy of "12"
This gives 1+5+3 = 9 values that are a multiple of 4
P(B) = 9/36 = (1*9)/(4*9) = 1/4
