3 years ago

In a population that is normally distributed that has a mean of 45 with a standard

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

5 0

I think I would be 5

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RUDIKE [14]

Answer:

$\approx \: 7.33 \: {cm}^{2}$

Step-by-step explanation:

Area of the blue shaded region

$= \frac{ \theta}{360 \degree} \times \pi r_1^2 - \frac{ \theta}{360 \degree} \times \pi r_2^2 \\ \\ = \frac{ \pi\theta}{360 \degree} ( r_1^2 - r_2^2) \\ \\ ( r_1 = 4 \: cm, \: \: r_2 = 3\: cm, \: \: \theta = 120 \degree) \\ \\ = \frac{ 3.14 \times 120 \degree}{360 \degree} ( 4^2 - 3^2) \\ \\ = \frac{ 3.14 }{3} \times 7 \\ \\ = \frac{21.98}{3} \\ \\ = 7.32666667 \\ \\ \approx \: 7.33 \: {cm}^{2}$

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3 years ago

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Step-by-step explanation:

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3 years ago

The average weight of a midsize car is 1 3/4 tons. The average weight of a compact car is 6/7 of the weight of a midsize car. Ho

Alborosie

6/7 of 1 3/4......turn the mixed number to an improper fraction...and " of " means multiply
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11111nata11111 [884]

The answer is 40 and 41

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