Answer:
$7,185 see below ↓
explanation:
With median, it is about the number that appears the most, and since the closest it gets is between $7,071 and $7,195, we have to pick the number that averages in-between which in this case is <em>7,185.</em>
Below, this ↓ array proves the logic.
<em />![\left[\begin{array}{ccc}7195&7185&7071\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7195%267185%267071%5Cend%7Barray%7D%5Cright%5D)
Ex 1
the number from 1 to 100, I'll call it x
= (((x + 11) * 6 - 3) / 3 + 5) / 2 - x
= ((6x + 66 - 3) / 3 + 5) / 2 - x
= ((6x + 63) / 3 + 5) / 2 - x
= (2x + 21 + 5) / 2 - x
= (2x + 26) / 2 - x
= x + 13 - x
= 13
finally geez
Ex 2
theres 16 teams.
after a team that loses twice they're out.
1 should be left, therefor 15 teams should be out.
15 * 2 = 30,
there should be 30 or 31 games if the last team alive lost 1 game.
Answer:
1.09
Step-by-step explanation:
I *really* wish I had work to show, but I just used a calculator as it is a simple division problem. Since you can do long divison, here are the steps! It is very hard to show on here, so I have typed it out:
Step 1: Estimate the answer by rounding. You'll use this estimate to check your answer later.
Step 2: If the divisor is not a whole number, then move the decimal place n places to the right to make it a whole number. Then move the decimal place in the dividend the same number of places to the right (adding some extra zeros if necessary.)
Step 3: Divide as usual. If the divisor doesn't go in evenly, add zeros to the right of the dividend and keep dividing until you get a 0 remainder, or until a repeating pattern shows up.
Step 4: Put the decimal point in the quotient directly above where the decimal point now is in the dividend.
Step 5: Check your answer against your estimate to see if it's reasonable.
Answer:
3
Step-by-step explanation:
1/5 × 15
= 15/5
= 3 (would love if you could mark me the brainliest :))
