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babunello [35]
2 years ago
9

5 small containers of capacity 16, 72, 12, 24 and 56 Litres are to be used to fill a bigger container. What is the capacity of t

he bigger container which can be filled by each of the above containers exactly without leaving a remainder when used seperately?
Mathematics
1 answer:
PIT_PIT [208]2 years ago
6 0

Answer: 1008

Step-by-step explanation:

Given

5 small containers of capacity 16,72,12,24, and 56 litres is required to fill a big container.

The volume of big container is the LCM of the 5 given containers

LCM(16,72,12,24,56)=1008

Therefore, the capacity of the bigger container is 1008 litres.

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AfilCa [17]

Answer:

  8,275,842 digits

Step-by-step explanation:

One more than the floor of the logarithm to the base 37 gives the number of digits. The change of base formula can be used.

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Expressed in the base-37 number system, P has 8275842 digits.

6 0
3 years ago
Pls help. I need it asap
Amiraneli [1.4K]

Answer:

18

Step-by-step explanation:

since the equation of AC is y=x-4 then the length of CB and AB must be the same. therefor its (6*6)/2

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2 years ago
If f(x)=3x²-5x+4, then f(-2) =
igomit [66]

Answer:

Step-by-step explanation:

First let's re-write the equation:

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If f(-2). then we can re-write the equation as:

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We must solve for exponent first:  (-2)² = 4

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Then solve for multiplication:

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Finally addition:

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4 0
2 years ago
The formula for calculating the density of an object is D=-, where m is mass and v is volume.
Over [174]

Answer:

M= D x V, V= M x D

Step-by-step explanation:

You just do the opposite of division since the original is:

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8 0
3 years ago
Could Someone give me a run down of how these problems are done? i used a calculator to get the answers but now i want to know h
morpeh [17]
It’s just the same as if there were no decimal point. but if there isn’t a number in the quotient on the left of the decimal like #15, then you just place a 0 and continue to the next dividend which is 50.

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