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3 years ago

140 degress increased by 65%

1 answer:

8 0

If a regular number is 100%, that means that the extra 65% will make it 165%. Doing 140*(165/100) we get 23100/100, or 231 degrees.

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What is the x intercept of the function x^3-5x^2-8x+48

Zinaida [17]

Answer:

(x+3)(x-4)^2

Step-by-step explanation:

= (x+3)(x^3-5x^2-8x+48)/(x+3)

= x (x^3-5x^2-8x+48)/(x+3)

= x^2-8x+16

= (x+3)(x-4)(x-4)

= (x+3)(x-4)^2

4 0

3 years ago

Read 2 more answers

Marcus is building a fence around his rectangular backyard. The length of his backyard is 75 3/4 ft, and the width is 81 1/4 ft.

Allisa [31]

Answer:

Step-by-step explanation:

Answer:

4,923.75ft²

Step-by-step explanation:

The area of the backyard = Length * width \

Area of the backyard = 75 3/4 * 81 1/4

Area of the backyard = 303/4 * 325/4

Area of the backyard = 6,154.6875ft²

If 3/4 of the fence is finished, the area of the finished part is expressed as;

Finished part = 1/5 * 6,154.6875

Finished part = 1,230.9375ft²

Part left unfinished = 6,154.6875-1,230.9375

Part left unfinished = 4,923.75ft²

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=4%20%20%20%7B%7D%5E%7Bx%20%7D%20%20%2B%206%20%7B%7D%5E%7Bx%7D%20%3D%209%20%7B%7D%5E%7Bx%7D%20%

Nookie1986 [14]

So, the value of x is 1.19

The question is an exponential equation

<h3>What is an exponential equation?</h3>

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

Since $4^{x} + 6^{x} = 9^{x}$ ,

Dividing through by 4ˣ, we have

$\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }$

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

$y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

$y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618$

Since y = (3/2)ˣ

Takung logarithm of both sides, we have

㏒y = ㏒(3/2)ˣ

㏒y = x㏒(3/2)

x = ㏒y/㏒(3/2)

x = ㏒y/㏒1.5

Since we do not have logarithm of a negative number, we use y = 1.618.

So, x = ㏒y/㏒1.5

x = ㏒1.618/㏒1.5

x = 0.2090/0.1761

x = 1.19

So, the value of x is 1.19

Learn more about exponential equation here:

brainly.com/question/11832081

#SPJ1

5 0

1 year ago

What is the equation of the line in slope intercept form through (-5,-3) and (6,1) ?

erastovalidia [21]

y - y1 = m (x - x1)

where m is the slope and (x1 , y1) is the point given

m = (y2-y1)\(x2-x1)

we have <span>(-5,-3) and (6,1)

so: m = (1- -3) / (6- -5) = (1+3)/(6+5) = 4/11

and the equation of the line is:
</span>y - y1 = m (x - x1)
y-1 = 4/11 (x-6)

simplify:

y = 4/11 x - 24/11 +1

$y= \frac{4}{11} x - \frac{13}{11}$

I hope that helps!

8 0

3 years ago

Help integrate: cot^3(x)

barxatty [35]

$\displaystyle\int\cot^3x\,\mathrm dx=\int\cot^2x\cot x\,\mathrm dx=\int(\csc^2x-1)\cot x\,\mathrm dx$
$\displaystyle=\int\csc^2x\cot x\,\mathrm dx-\int\cot x\,\mathrm dx$

For the first integral, substitute $y=\cot x$ so that $\mathrm dy=-\csc^2x\,\mathrm dx$ . This leaves you with two standard integrals,

$=\displaystyle-\int y\,\mathrm dy-\int\cot x\,\mathrm dx$
$=-\dfrac12y^2+\ln|\cot x+\csc x|+C$
$=-\dfrac12\cot^2x+\ln|\cot x+\csc x|+C$

7 0

3 years ago