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e-lub [12.9K]
2 years ago
7

Rhosanda is downloading a file from the Internet. The size of the file is 7.45 MB. The file is downloading at the rate of 0.095

MB per second. How many seconds will it take to download the entire file? Round your answer to the nearest second.
Mathematics
1 answer:
elixir [45]2 years ago
7 0
7.45/0.095 = 78 seconds
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Part III: Find the unknown side lengths, AB and BC. HINT: Use either the Pythagorean Theorem or special right triangle propertie
yaroslaw [1]

The measurement of sides AB, BC, and AC will be 3 units,3 units, and 3√2 units respectively.

<h3>What is a right-angle triangle?</h3>

If any of its inner angles is 90 degrees, the triangle is said to be right-angled. Another term for this triangle is the right triangle or 90-degree triangle.

From the given triangle, it is observed that one of the angles is 90°, showing the given triangle is a right-angle triangle.

From the Δ ABC we found;

tan 45° = AB/BC

1=AB/BC

AB=BC

sin 45° = AB/AC

(1/√2)=AB/AC

AC = √2 AB

From the graph, it is observed that

AB=BC =3 units

AC=  √2 AB

AC = 3√2 units

Hence, the measurement of sides AB, BC, and AC will be 3 units,3 units, and 3√2 units respectively.

To learn more about the right-angle triangle, refer;

brainly.com/question/3770177

#SPJ1

4 0
1 year ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
Read 2 more answers
Can anyone please help anyone bro
xxTIMURxx [149]
F(x) and g(x) were inverse functions, then if f(a) = b, then g(b) = a

f(x) = (5x+1) / x g(x) = x / (5x+1)

f(1) = 6, but g(6) = 6/31 ≠ 1

So, f(x) and g(x) are NOT inverse functions.
5 0
2 years ago
6.24 x 10-5 - 4.091 x 103 =
castortr0y [4]
Is the 10 taking away 5 or was it meant to me 10.5 ?
6 0
3 years ago
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VERY URGENT PLEASE HELP!!!!
Triss [41]

Answer:

61 + 4x = y

Step-by-step explanation:

61 : starting tree height

4x : 4 times however many months pass

y : total height after x months.

4 0
2 years ago
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