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SSSSS [86.1K]
3 years ago
12

How do I simplify this expression?​

Mathematics
2 answers:
serious [3.7K]3 years ago
8 0

Answer:

cube 8 so 8x 8x8=512divide by three 170.6

Step-by-step explanation:

170.666666667 is your answer please mark me brainliest

ohaa [14]3 years ago
7 0

Answer:

2

Step-by-step explanation:

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Which equation describes this line (1,10) (-3,2)
zubka84 [21]
Find the slope first:
m=y2-y-1/x2-x1

m=2-10/-3-1
m= -8/-4
m= 2

Select a point & put into y=mx+b to find b.
y=mx +b
10 =2(1) + b
10 =2 +b
8 = b

Rewrite the equation with your slope &intercept:

y=2x + 8

That's ^ the equation that describes your line!
6 0
3 years ago
Simplify <br>3x2 + x + 2x2​
jenyasd209 [6]

Answer:

10+ x

Step-by-step explanation:

Follow me please for answering the question

8 0
3 years ago
Read 2 more answers
Please help on question 12 or 13 as soon as possible
Anna007 [38]

Answer:

to know the summation of angles: (n-2)*180

here (n) represent numbers of sides

12)we have 5 sides (n=5)

(5-2)*180=540

x=540-(105+135+92+87)=121

13)we have 8 sides (n=8)

(8-2)*180=1080

x=1080-(116+158+141+124+136+132+129)=144

I hope it will help

3 0
2 years ago
A radio telescope has a parabolic surface, as shown below.
krek1111 [17]
OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0

Because the roots of the equation are 0 and 12, we know the formula is therefore of the form

y = ax(x - 12), for some a

So put in x = 6

-9 = 6a(-6)

9 = 36a

a = 1/4

So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x

The gradient of this is dy/dx = 0.5x - 3

The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8

Gradient of the parabolic mirror at x = 4 is -1

So the gradient of the normal to the mirror at x = 4 is therefore 1.

Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.

So the focal point is at y = -8, i.e. 1 metre above the back of the dish.
5 0
2 years ago
Need help don’t know what I’m doing
docker41 [41]
This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language) 
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^

8 0
3 years ago
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