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coldgirl [10]
3 years ago
15

What are two equivalent ratios for 8/10?

Mathematics
2 answers:
True [87]3 years ago
5 0
It can be divded by 2 and you will get 4/5
Varvara68 [4.7K]3 years ago
4 0
To find this, multiply both the numerator and denominator by the same number. For example, 8 x 8 =64, and 10 x 8=80, so 64/80 would be an example of an equivalent ratio. Others could be 16/20 or 48/60. Hope this helps.
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adelina 88 [10]
The correct answer is D
8 0
3 years ago
Read 2 more answers
Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos
Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$ P_{1} = (- 1, 4) $

$ P_{2} = (6, 2) $    and

$ P_{3} = (4, - 5) $

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $ (x_1, y_1) $ and $ (x_2, y_2) $ is:

                                 $ \sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+}   \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}} $

Length between $ P_1 $ and $ P_{2} $ , (Side 1) :

$ (x_1, y_1) = (- 1, 4) $     and

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2 $

$ = \sqrt{7^2 + 2^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53}} $

Length of Side 1 = $  \sqrt{\textbf{53}} $ units.

Distance between $ P_1 $ and P_2 , (Side 2):

$ (x_1, y_1) = (-1, 4) $

$ (x_2, y_2) = (4, - 5) $

Distance = $ \sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2 $

$ = \sqrt{ 25 + 81 } $

$ = \sqrt{\textbf{106}} $

Length of Side 2 = $ \sqrt{\textbf{106}} $ units.

Distance between $ P_2 $ and $ P_3 $ , Side 3 :

$ (x_1, y_1) = (4, 5) $

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53} $

Length of Side 3  = $ \sqrt{\textbf{53}} $ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$ \bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2 $

i.e, 53 + 53  = 106

Hence, the triangle is a right - angled triangle as well.

7 0
4 years ago
You have $3 and earn $7.50 for each car you wash. Write an equation in two variables that represents the total amount a
worty [1.4K]

Answer:

f(x)= 7.5x + 3

Step-by-step explanation:

you have 3 dollars just there, and you get 7.50 per car wash, so that is the x

5 0
4 years ago
Suppose that the functions r and s are defined for all real numbers x as follows.
mixas84 [53]
ANSWER

Given

r(x) = x - 1


and

s(x) = 3 {x}^{2}
ANSWER TO QUESTION 1

(r + s)(x) = r(x) + s(x)


(r + s)(x) = x - 1 + 3 {x}^{2}


(r + s)(x) =  3 {x}^{2}  + x - 1



ANSWER TO QUESTION 2



(r \times s)(x) = r(x) \times s(x)


(r \times s)(x) = (x - 1) \times 3 {x}^{2}


(r \times s)(x) = 3 {x}^{3}  - 3 {x}^{2}

ANSWER TO QUESTION 3

( r - s)(x) = r(x) - s(x)



( r - s)(x) = x - 1 - 3 {x}^{2}


( r - s)( - 3) =  (- 3) - 1 - 3 ({ - 3}^{2} )



( r - s)( - 3) =   - 4 - 3  \times 9



( r - s)( - 3) =   - 4 - 27 =  - 31

4 0
3 years ago
A standard deck of cards contains 52 cards. The cards have 4 different suits: clubs, diamonds, hearts, and spades. For each suit
Taya2010 [7]

Answer:

a. 108336, b. 480200

Step-by-step explanation:

a. No. of ace cards = 4

No. of non ace cards= 48

We draw 5 cards

So,

No. of ways of 2 aces = C(4,2) C(48,3)

No. of ways of 3 aces = C(4,3) C(48,2)

No. of ways of 4 aces = C(4,4) C(48,1)

Hence

No. of ways of 2 or more aces

= C(4,2) + C(48,3) + C(48,3) + C(4,3)C(48,2) +C(4,4)C(48,1)

= 6(17296) + 4(1128) + (48)

= 108336

b. No of ways any 5 cards can be chosen = C(52,5)

No. of ways kings of diamonds or queen of hearts is chosen = C(50,5)

Hence

No. of ways of choosing king of diamonds, queen of hearts or both = C(52,5) – C(50,5)

= 480200

4 0
3 years ago
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