Answer:
187.5 or rounded off to 188 white, terminal flowers
Explanation:
Let red=R and white=r where R>r; axial=A and terminal=a where A>a
The parents are true-breeding which means that they are homozygous.
P: RRAA x rraa
F1: RrAa
We then cross two plants from the F1 generation
RrAa x RrAa
To find out the probability we look at the different traits individually
Rr x Rr
yielding 1/4 RR (red), 1/2 Rr (red), 1/4 rr (white)
Aa x Aa
yielding 1/4 AA (axial), 1/2 Aa (axial), 1/4 aa (terminal).
We determine which F2 genotypes would allow for red, terminal flowers.
RRaa and Rraa
Then we use the multiplication rule to determine the probability of these occurring
RRaa: 1/4 x 1/4 = 1/16
Rraa: 1/2 x 1/4 = 1/8
Next we use the addition rule
1/16 + 1/8 = 3/16
To find out the number of these plants within the 1000 F2 plants we multiply the probability with 1000
3/16 x 1000= 187.5 red, terminal flowers
