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SashulF [63]
3 years ago
12

Adilation produces a larger figure. Which is a possible scale factor?

Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:scale factor more than 1

Step-by-step explanation:if a scale factor is more than 1,it enlarges the shape ...meaning the image will be larger than the original shape

If a scale factor is less than one,it brings reduction to the shape...meaning the image is smaller than the original shape

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Is x-3/5 = N and N = 6, what is the value of x?
scZoUnD [109]

Answer:

x = 33/5

Step-by-step explanation:

x - 3/5 = n.......n = 6

so we sub

x - 3/5 = 6......add 3/5 to both sides

x = 6 + 3/5...convert using common denominator of 5

x = 30/5 + 3/5

x = 33/5 <===

check...

x - 3/5 = 6

33/5 - 3/5 = 6

30/5 = 6

6 = 6 (correct)...so it checks out

5 0
3 years ago
Read 2 more answers
What is 150 divided by 625 step by step
Levart [38]

Answer:

150 dived by 625 is 0.24 I'm not sure how to explain it

6 0
3 years ago
The quotient of ninety five and a number is what
djyliett [7]
This is how you solve it..
95/n=n
You could put 5 in and get 95/5=19.
8 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
a box cost $2.48, but it is on sale for $1.49. How much do you save on one box when bought on sale? Now how much would you save
Thepotemich [5.8K]

Answer:

1. $0.99

2. $1.98

Step-by-step explanation:

1. From the question we have

Cost of box = $2.48

Selling price = $1.49

That is the box is discounted from $2.48 to $1.49

Therefore, amount saved = $2.48 - $1.49 = $0.99

2. The amount saved from buying a second box is hence;

2 × $0.99 = $1.98

Hence, as the number of boxes bought increases, the amount saved increases

5 0
3 years ago
Read 2 more answers
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