How many one inch cubes do you need to create an edge with a length of 5 inches

1 answer:

5 0

Actually you would need 125 inches cube:

5 inches of length × 5 inches of height × 5 inches of width which equals to 125 inches cube !

I hope you understood my brief explanation. And please consider marking this awnser as Branliest. Thank you ! :)

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Please help me with this please?

adell [148]

The answer has to be C

3 0

3 years ago

Find the value of f. What can you do to Both Sides?f - ⅔ = ¼

Thepotemich [5.8K]

Answer:

11/12

Step-by-step explanation:

<h2><u>Value of F </u></h2>

to find the value of f , we need to move the -2/3 to the other side of the equal sign.

$f - \frac{2}{3} = \frac{1}{4}$

<u><em>Note </em></u>: is you move a number from one side of the equal sign to the other, this changes the sign of the number ( eg , -2/3 becomes +2/3)

$f = \frac{1}{4} + \frac{2}{3}$

f = $\frac{11}{12}$

<h3><u>hence the value of f is 11/12 </u></h3>

7 0

3 years ago

Figure ABCD is graphed on a coordinate plane.

Phoenix [80]

1. BC is 1+3=4 (units)

2. AD is 3+5= 8 (units)

3. Draw the altitude CH from point C, as shown in the figure.

4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.

5. $CD^2=HD^2+CH^2$

$CD^2=2^2+4^2=4+16=20$

$CD= \sqrt{20}= \sqrt{4*5}= \sqrt{4} * \sqrt{5}=2 \sqrt{5}= 4.47$

6. AB=CD=4.47 because the trapezoid is isosceles.

7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)