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4 years ago

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Tim knows the volume and base area of a wooden chest that is in the shape of a rectangular prism. If the volume is 5/24 of a cub

ic unit and the base area is 1/5 of a square unit, what is the height of the chest?

1 answer:

Leto [7]4 years ago

6 0

Answer: The height of the chest is 11/24

Step-by-step explanation:

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Alicia desea hacer un viaje desde la ciudad de los Mochis a tijuana el boleto en autobús cuesta 2,500 pesos pero por fechas espe

mylen [45]

Answer:

Alicia pagara MX$1,700.

Step-by-step explanation:

A 32% discount (descuento) would come to 0.32(MX$2,500) = MX$800.

Subtracting MX$800 from MX$2,500 yields MX$1,700.

Alicia pagara MX$1,700.

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3 years ago

Guys, I really need help!

TiliK225 [7]

Answer:

The answer is

$p = \frac{ - 3}{1000} n + 97$

Step-by-step explanation:

We have the points (2000,91) and (5000,82)

Then

$m = \frac{91 - 82}{2000 - 5000} = \frac{ - 3}{1000} \\ to \: find \: the \: b \\ 91 = \frac{ - 3}{1000} \times 2000 + b \\ b = 97 \\ then \: the \: equation \: is \: \\ p = \frac{ - 3}{1000} n + 97$

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3 years ago

In Northern Yellowstone Lake, earthquakes occur at a mean rate of 1.3 quakes per year. Let X be the number of quakes in a given

hichkok12 [17]

Answer:

a) Earthquakes are random and independent events.

b) There is an 85.71% probability of fewer than three quakes.

c) There is a 0.51% probability of more than five quakes.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

In Northern Yellowstone Lake, earthquakes occur at a mean rate of 1.3 quakes per year, so $\mu = 1.3$

(a) Justify the use of the Poisson model.

Earthquakes are random and independent events.

You can't predict when a earthquake is going to happen, or how many are going to have in a year. It is an estimative.

(b) What is the probability of fewer than three quakes?

This is $P(X < 3)$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.3}*1.3^{0}}{(0)!} = 0.2725$

$P(X = 1) = \frac{e^{-1.3}*1.3^{1}}{(1)!} = 0.3543$

$P(X = 2) = \frac{e^{-1.3}*1.3^{2}}{(2)!} = 0.2303$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2725 + 0.3543 + 0.2303 = 0.8571$

There is an 85.71% probability of fewer than three quakes.

(c) What is the probability of more than five quakes?

This is $P(X > 5)$

We know that either there are 5 or less earthquakes, or there are more than 5 earthquakes. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 5) + P(X > 5) = 1$

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.3}*1.3^{0}}{(0)!} = 0.2725$

$P(X = 1) = \frac{e^{-1.3}*1.3^{1}}{(1)!} = 0.3543$

$P(X = 2) = \frac{e^{-1.3}*1.3^{2}}{(2)!} = 0.2303$

$P(X = 3) = \frac{e^{-1.3}*1.3^{3}}{(3)!} = 0.0980$

$P(X = 4) = \frac{e^{-1.3}*1.3^{4}}{(4)!} = 0.0324$

$P(X = 5) = \frac{e^{-1.3}*1.3^{5}}{(5)!} = 0.0084$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.2725 + 0.3543 + 0.2303 + 0.0980 + 0.0324 + 0.0084 = 0.9949$

Finally

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9949 = 0.0051$

There is a 0.51% probability of more than five quakes.

5 0

3 years ago

If 30,000 is divided by 10 and then divided by 10 again what will be the resulting number? Help please

djverab [1.8K]

Answer:

300

Step-by-step explanation:

30,000/10 = 3,000

3,000/10 = 300

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3 years ago

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Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

Semenov [28]

Answer:

88.26 square yards

Step-by-step explanation:

Big rectangle: A = 4 x 12 = 48

Quarter circle: A = 1/4 x 3.14 x 6^2 = 28.26

Small rectangle: A = 2 x 6 = 12

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3 years ago

Read 2 more answers