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N76 [4]
3 years ago
13

A patrol man gives a driver speeding ticket if the driver speed is greater than 15% over the posted speed limit . If the speed l

imit is 40 mph what is the highest speed that a driver can go without receiving a ticket?
Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0

Answer:

46 mph

Step-by-step explanation:

Hello,  I  can help you with this.

According to the question  the speed limit is 40 mph, if the driver speed is greater than 15% over the posted speed limit,so you need to find 115 of 40 mph

you can easily solve this by using a rule of three.

Step 1

if

40 mph⇔ 100%

x mph ⇔ 115%

x(115 % of 40)

do the relation and isolate x

\frac{40}{100}=\frac{x}{115}\\\frac{40*115}{100}=x\\ x=\frac{4600}{100}\\ x=46

x=46 mph

so,  the highest speed that a driver can go without receiving a ticket 46 mph

Have a great day

Maru [420]3 years ago
3 0
10%of 40=4 5% of 40=2 4+2=6 40+6=46 so the answer is 46mph
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Triangle ABC has been reflected over the x-axis to create triangle A'B'C'. Which of the following statements is true?
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Answer:

A ' = (-2, -3)

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C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as

Applying this rule to the three given points will mean....

Point A = (-2, 3) becomes A ' = (-2, -3)

Point B = (0, 3) becomes B ' = (0, -3)

Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

Step-by-step explanation:

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A. Suppose you have just inherited a sum of money. Let’s say you choose to invest the money. How much did you inherit? Choose an
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Amount =$48003.20

Step-by-step explanation:

Here apply the compound interest formula;

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In our case, the amount after investing will be;

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An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
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Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

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Then we have:

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c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

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P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

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The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

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