To find what the number is, we need to set up proportional fractions.
Currently, we have 8% of a number is 20.
To set up our fractions, put 100% under 8% as a fraction first.
It should look like this: 8/100 (hint: per-cent means per-hundred).
Now, we have 20 out of a number, x. This is because we are claiming that 20 is 8% of a number (if we just reword the question without changing the concept).
It should look like this: 20/x.
Our proportional fractions are:
20/x = 8/100.
To solve for this, we need to cross-multiply the denominator of 8/100 (bottom number, 100) with the numerator of 20/x (top number, 20).
This product equation should look like this:
20 x 100 (when simplified, we get 2000).
Now, we need to cross multiply the numerator of 8/100 (top number, 8) with the denominator of 20/x (bottom number, x).
This product equation should look like this:
8x.
Now that we've cross-multiplied, set our two products as an equation.
8x = 2000.
To solve for x, divide both sides by 8 (remember, what you do to one side of an equation, you must do it to the other).
8x / 8 = x
2000 / 8 = 250.
x = 250
Your final answer is:
8% of 250 is 20.
I hope this helps!
Answer:
? = 30
Step-by-step explanation:
If the triangles are similar, then the only way I see this working is the sides measuring 63 and 54 are corresponding. The sides measuring 56 and 48 are corresponding. That leaves the sides measuring 35 and ? corresponding.
Set up a proportion.
63/54 = 35/?
63? = 54 * 35
63? = 1890
? = 30
Answer:
<em>6,174</em>
Step-by-step explanation:
(-33 * - 78) + (5 * 8 * 9 * 10)
Remove the brackets:
-33 * - 78 + 5 * 8 * 9 * 10
Solve like so:
-33 * - 78 = 2,574
5 * 8 * 9 * 10 = 3,600
(2,574) + (3,600)
2,574 + 3,600 = 6,174
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Answer:
69, nice
Step-by-step explanation:
118-49=69
Answer:
Interval [b,c] and interval [c,d]
Step-by-step explanation:
a(-5,0)
b(-1,2)
c(4,3)
d(11,4)
The average rate of change is the the total rise over the total run.
The Rise means the vertical increase and the Run means horizontal incease.
For interval [a,b]
rate of change is 
For [b,c]
For [c,d]
