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MAXImum [283]
3 years ago
7

16z+29z=pz-v solve for z

Mathematics
2 answers:
Margarita [4]3 years ago
8 0
<span>16z + 29z=pz - v

45z - pz = -v

z(45 - p) = -v

z = </span>\frac{-v}{(45 - p)}
timurjin [86]3 years ago
7 0

Answer:

z = \frac{v}{45 -p}.

Step-by-step explanation:

Given : 16z + 29z = pz - v .

To find : solve for z.

Solution :  We have given

16z + 29z = pz - v .

On adding the like terms.

45z = pz - v .

On Subtracting both sides by pz .

45z - pz = v .

On taking common  z from left hand side.

z (45 -p ) = v .

On dividing both sides by 45 - p .

z = \frac{v}{45 -p}.

Therefore, z = \frac{v}{45 -p}.

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3 years ago
Laura drives a garbage truck that weighs 3 tons. She picked up 2 tons of recyclables. What is the total weight in pounds of the
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Answer:

Step-by-step explanation:

Total weight=The garbage truck weight + recyclables weight =3 tons + 2 tons = 5 tons

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3 years ago
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A line passes through the point (8,-9) and has a slope of -5/2. Write an equation in slope intercept form for this line.
noname [10]

Answer:

y = - \frac{5}{2} x + 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{5}{2} , then

y = - \frac{5}{2} x + c ← is the partial equation

To find c substitute (8, - 9) into the partial equation

- 9 = - 20 + c ⇒ c = - 9 + 20 = 11

y = - \frac{5}{2} x + 11 ← equation of line

4 0
3 years ago
Given: ABC is a right triangle with right angle C. AC=15 centimeters and m∠A=40∘ . What is BC ? Enter your answer, rounded to th
konstantin123 [22]

In order to answer this question, the figure in the first picture will be helpful to understand what a right triangle is. Here, a right angle refers to 90\°.


However, if we want to solve the problem we have to know certain things before:


In the second figure is shown a general right triangle with its three sides and another given angle, we will name it \alpha:


  • The side <u>opposite to the right angle</u> is called The Hypotenuse (h)
  • The side <u>opposite to the angle \alpha</u> is called the Opposite (O)
  • The side <u>next to the angle \alpha</u> is called the Adjacent (A)

So, going back to the triangle of our question (first figure):


  • The Hypotenuse is AB
  • The Opposite is BC
  • The Adjacent is AC

Now, if we want to find the length of each side of a right triangle, we have to use the <u>Pythagorean Theorem</u> and T<u>rigonometric Functions:</u>


Pythagorean Theorem


h^{2}=A^{2} +O^{2}    (1)  


Trigonometric Functions (here are shown three of them):


Sine: sin(\alpha)=\frac{O}{h}    (2)


Cosine: cos(\alpha)=\frac{A}{h}    (3)


Tangent: tan(\alpha)=\frac{O}{A}   (4)



In this case the function that works for this problem is cosine (3), let’s apply it here:


cos(40\°)=\frac{AC}{h}    


cos(40\°)=\frac{15}{h}    (5)


And we will use the Pythagorean Theorem to find the hypotenuse, as well:



h^{2}=AC^{2}+BC^{2}    


h^{2}=15^{2}+BC^{2}    (6)


h=\sqrt{225+BC^2}   (7)



Substitute (7) in (5):


cos(40\°)=\frac{15}{\sqrt{225+BC^2}}    


Then clear BC, which is the side we want:


{\sqrt{225+BC^2}}=\frac{15}{cos(40\°)}


{{\sqrt{225+BC^2}}^2={(\frac{15}{cos(40\°)})}^2


225+BC^{2}=\frac{225}{{(cos(40\°))}^2}


BC^2=\frac{225}{{(cos(40\°))}^2}-225


BC=\sqrt{158,41}


BC=12.58


Finally BC is approximately 13 cm



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