The required probability of success is given by 0.98906500
Assume the random variable X has a binomial distribution with the given probability of obtaining a success.
P(X<5), n=6, p=0.3
<h3>What is binomial distribution?</h3>
In binomial distribution for number trials we are investigating the probability of getting a success remain the same.
n = number of trails,
p = probability of success
x = the number of success
p(x<5) = P(x=0)+ p(x=1) + p(x=2)+p(x=3)+p(x=4)
= 
p(x<5) = 0.98906500
Thus the required probability of success is given by 0.98906500
Learn more about Binomial distribution here:
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75 + 10 = 85
85 - 10 = 75
85 - 75 = 10
There is nothing to solve for.
9514 1404 393
Answer:
- straight time: $699.20
- overtime: $165.60
- total pay: $864.80
Step-by-step explanation:
(a) Maria's straight time pay is ...
(38 h)×($18.40 /h) = $699.20
__
(b) Maria's overtime pay is ...
(6 h)×(1.5×$18.40 /h) = $165.60
__
(c) Her total pay is the sum of her straight time pay and her overtime pay:
$699.20 +165.60 = $864.80