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netineya [11]
4 years ago
7

Multiply 3⁄4 × 16⁄9 .

Mathematics
2 answers:
valentina_108 [34]4 years ago
6 0

Answer:

OK so basically...

4/3

Step-by-step explanation:


Citrus2011 [14]4 years ago
5 0
Just multiply numerator × numerator and denominator × denominator...

3/4 × 16/9 =
48/36

now reduce

48/36 = 4/3 or 1 1/3
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Answer:

8n³ + 4

Step-by-step explanation:

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3 years ago
3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

y=2x

x=\frac{y}{2}

\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

R_{o} = x = \frac{y}{2}

R_{i} = x= (\frac{y}{2}) ^{4}

a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

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2 years ago
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lesya692 [45]

Answer:

There are 112 days in 16 weeks

8 0
3 years ago
Standard form of a line passing through points (1, 3) and (-2, 5)
____ [38]

Answer:

<h2>2x + 3y = 33 </h2>

Step-by-step explanation:

As we move from (-2, 5) to (1, 3), x increases by 3 and y decreases by 2.

Hence, the slope of this line is m = rise / run = -2/3.

Start with the slope-intercept form y = mx + b.

Substitute 3 for y and 1 for x and -2/3 for m:

3 = (-2/3)(1) + b.

Remove fractions by mult. all three terms by 3:

9 = -2 + b, so b = 11, and y = (-2/3)x + 11

Again, mult. all three terms by 3:

3y = -2x + 33, or, in standard form,

<h2>2x + 3y = 33 </h2>
6 0
3 years ago
Could you help me understand cross sections of three-dimenstional object its harder than it sound.​
umka21 [38]

A section, or cross-section, is a view of a 3-dimensional object from the position of a plane through the object. A section is a common method of depicting the internal arrangement of a 3-dimensional object in two dimensions. It is often used in technical drawing and is traditionally crosshatched.

Cross sections of three-dimensional objects are two-dimensional shapes of various sizes. They may be parallel to a side or base of the object or at an angle to these surfaces. A cross section may resemble the shape of the object’s side or base, or it may have a completely different shape.

5 0
3 years ago
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