Question

Write the point-slope form of the line passing through (2, -12) and parallel to y=3x.

Answer 1

Hello :
the line has same slope : y=3x       3 is the slope
 the point-slope form is : 
y-(-12) = 3(x-2)
y+12 = 3(x-2)

Answer 2

Answer:

$y = 3x-18$

Step-by-step explanation:

Given : $y=3x$

To Find: Write the point-slope form of the line passing through (2, -12) and parallel to y=3x.

Slope of parallel lines are equal .

Standard equation of line : $y = mx+c$

Where m is the slope

So, on comparing with given equation the slope is 3

So, the line parallel to the given line will also have a slope 3

So, the equation of parallel line = $y = 3x+c$  --1

Now we are given that this parallel lines passes through (2,-12)

So, substitute (2,-12) in --1

$-12 = 3(2)+c$

$-12 =6+c$

$c=-18$

Substitute the value of c in 1

$y = 3x-18$

Hence the point-slope form of the line passing through (2, -12) and parallel to y=3x is  $y = 3x-18$