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NISA [10]
3 years ago
10

Refer to the dog weights box-and-whisker plot in answering the question. In which quarter are the data least concentrated?!

Mathematics
1 answer:
umka21 [38]3 years ago
4 0

Answer:

c

Step-by-step explanation:


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() + -8= -6 what is the awnser
Mariana [72]

Answer:x=2

Step-by-step explanation:

change () to x

x + -8= -6

-6+8=2

x=2

5 0
4 years ago
Find the measure of the missing angle *
lubasha [3.4K]

Answer:

21°

Step-by-step explanation:

we know that every single triangle has to equal 180°

we have all 3 angles 90° 34° 35° which equal 159°

so we take 180°-159° and your answer is 21°

6 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
What is the surface area of a sphere whose volume is 28811 ins , n
Lina20 [59]
Volume=(4/3)pir^3
volume=288pi
288pi=(4/3)pir^3
divid eobht sides by pi
288=(4/3)r^3
multiply both sides by 3/4 to clear fraction (4/3 times 3/4=12/12=1)
216=r^3
cube root both sides
6=r

surface area=4pir^2
surface area=4pi6^2
surface area=4pi36
surface area=144pi in^2
8 0
3 years ago
Question 3 (0.5 points)
nekit [7.7K]

Answer:

0.72

Step-by-step explanation:

7.25+2.35=9.6

9.6÷100=0.096

0.096×7.5=0.72 the tax

5 0
3 years ago
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