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2 years ago

Two fair six sided dice are thrown. Find the probability that both dice land on 6

Mathematics

1 answer:

-BARSIC- [3]2 years ago

3 0

Two dice ⇒ 6*6=36 possible results
Both dice land on 6 ⇒ 1 possibility

P=1/36

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Something added by -8 equals 20

LiRa [457]

Answer:

28 is added by -8 equals 20

Step-by-step explanation:

The equation to calculate something added by -8 equals 20 is as follows:

x-8 = 20

x = 20+8

x = 28

28 is added by -8 equals 20

8 0

2 years ago

Read 2 more answers

Find the missing side of this right

navik [9.2K]

Answer:

x = 13

Step-by-step explanation:

First start with the blank equation

$a^{2} + b^{2} = c^{2}$

Plug in the legs and hypotenuse. Remember c squared is always the hypotenuse.

$5^{2} + 12^{2} = c^{2}$

Then solve

25 + 144 = $c^{2}$

169 = $c^{2}$

$\sqrt{169} = \sqrt{c^{2} }$

c = 13

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2 years ago

The sum of eight and two, subtracted from x<br> a. x + (8 - 2)<br> b. x - (8 + 2)

Lesechka [4]

Answer B is correct. Sum is the answer to an addition problem, so sum of 8 and 2 would be 8+2.

7 0

2 years ago

What is 12-2x6 + 2/2 ?

garri49 [273]

$12-2*6 + \frac{2}{2}= \\
12-12+1 = 0 + 1 = 1$

7 0

2 years ago

Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff

liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places. The formula for Newton's Method is

$x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }$

If our function is

$f(x)=x^5+x-6$

then the first derivative is

$f'(x)=5x^4+1$

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2. I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0

2 years ago