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Fed [463]
3 years ago
10

What’s the missing part

Mathematics
2 answers:
Alchen [17]3 years ago
7 0
It should be 15sqrt(3)/2
Musya8 [376]3 years ago
7 0
Hey there...........

My answer is.....................

from what i have concluded it is ...............
                                                       15sqrt(3)/2


hope it helps
                      thank you.


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Whats the answer to 1/4 times 4/7
timama [110]
So you are multiplying the fractions together. You do not need a common denominator.  You multiply the numerators together and the denominators to get your new fraction.  
1x4=4
4x7=28
4/28
This fraction can now be simplified by dividing the numerator and denominator by 4
4/28x4/4
1/7
3 0
4 years ago
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
4 years ago
Using elimination to solve the system 2x + y = 8 and x + y = 4, which of the following could be the first step?
wolverine [178]
Answer: the option A.

The elimination method consist is adding the two equations in a way that one variable be eliminated..

In order to do that you might have to manipulate on of the equations prior to add the two equations.

In this case, ff you multiply the second equation by - 1 you will get

  - x - y = - 4

which you can add to the first equation

   2x + y = 8 to eliminate the y.

 
4 0
4 years ago
A scale model of the Washington monument is 18 inches tall and the base is 2.5 inches wide. If the actual monument is approximat
d1i1m1o1n [39]

Answer:

77.1 feet

Step-by-step explanation:

<u>Scale model:</u>

Height = 18 inches

Width = 2.5 inches

<u>Actual monument:</u>

Height = 555 feet

Width = x feet

Write a proportion:

\dfrac{\text{Scale height}}{\text{Actual height}}=\dfrac{\text{Scale width}}{\text{Actual width}}\\ \\ \\\dfrac{18 \ inches}{555\ feet}=\dfrac{2.5\ inches}{x\ inches}\\ \\ \\x=\dfrac{555\ feet\cdot 2.5\ inches}{18\ inches}\approx 77.1\ feet

8 0
3 years ago
PLZ HELP...IM GOING TO CRYYYY PLZ..I WILL MARK BRAINLIEST.
IrinaK [193]

Answer:

x=10

y=30

Step-by-step explanation:

x=-2y+70

x=-2*3x+70

x=-6x+70

7x=70

x=10

y=3x

y=3*10

y=30

8 0
3 years ago
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