All categories

4 years ago

What is ratios and how is it solved

1 answer:

7 0

A ratio is how many times one number can go into another for example 1:2 is a ratio so say you had 10 and 20 what is the ratio of ten to 20 it would 1:2 because 10 is half of 20 and half of 2 is one

You might be interested in

Please help me thank you very much

Aleks [24]

Question 1:

Match the letters/points that correspond to each other.
All choices start with "EAK", so that's our reference.
For the second triangle, we get AGK.
For the last triangle, we get EGA.

Question 2:

For this, just take the mean of 5 and 12.

$\frac{5+12}{2}$
$\frac{17}{2} =8 \frac{1}{2}$

Hope this helps! :)

4 0

3 years ago

What is the value of the underlined -195

motikmotik

What number is underlined??????

4 0

3 years ago

Read 2 more answers

Need help with math homework

Pavel [41]

Hello!

The answer for A is:

$X1=-1\\X2=5$

The answer for B is: The rocket will hit the lake surface in 5 seconds.

Defining the terms:

$a=-16\\b=64\\c=80\\$

So, replacing it in the quadratic equation (it's given to you in the exercise)\\

$x=\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}$

$x=\frac{-64+-\sqrt{64^{2}-4*-16*80 } }{2*-16}$

$x=\frac{-64+-\sqrt{64^{2}+5120} }{-32}=\frac{-64+-\sqrt{4096+5120} }{-32}\\x=\frac{-64+-\sqrt{9216} }{-32}=\frac{-64+-\ 96 }{-32}\\x=\frac{-64+-\ 96 }{-32}\\x1=\frac{-64+\ 96 }{-32}=\frac{32}{-32} =-1\\\\x1=\frac{-64-\ 96 }{-32}=\frac{-160}{-32} =5\\$

We are working with a quadratic equation, so we will have two possible results,

$X1=-1\\X2=5\\$

Now, we are asked to find the time, time can not be a negative value, we have to discard X1 (-1) since it's a negative value, knowing that, the rocket will hit the lake after 5 seconds.

Have a nice day!

5 0

4 years ago

The ratio of the measure of the acute angle in a right triangle is 1/2 . Find the measures of the two angles

AleksandrR [38]

30° and 60°.

<h3>Further explanation</h3>

We will solve the problem of the measures of angles in the triangle.

Recall this condition:

The acute angle ⇒ an angle of less than 90°.
The right angle ⇒ an angle of exactly 90°.
A right triangle ⇒ a triangle in which one angle is a right angle.
The interior angles ⇒ the angles inside a triangle.
All the interior angles in a triangle , i.e., $\boxed{ \ \angle A + \angle B + \angle C = 180^0 \ }$

<u>Given that:</u>

The ratio of the measure of the acute angle in a right triangle is ¹/₂.

<u>Question:</u>

Find the measures of the two angles.

<u>The Process:</u>

We call it the triangle ABC. An interior angle inside is a right angle, e.g., ∠A = 90°.

From the ratio of two other acute angles, i.e., 1: 2, we call it ∠B = x and ∠C = 2x.

Let's arrange the three angles in ABC triangle as follows:

$\boxed{ \ 90^0 + x + 2x = 180^0 \ }$

Both sides subtracted by 90°.

$\boxed{ \ x + 2x = 180^0 - 90^0 \ }$

$\boxed{ \ 3x = 90^0 \ }$

Both sides divided by 3.

We get $\boxed{ \ x = 30^0 \ }$

We substitute the value of x back into B and C.

$\boxed{\boxed{ \ \angle B = x\ } \rightarrow \boxed{ \ \angle B = 30^0 \ }} \\\boxed{\boxed{ \ \angle C = 2x\ } \rightarrow \boxed{ \ \angle C = 60^0 \ }}$