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Airida [17]
4 years ago
15

What is ratios and how is it solved​

Mathematics
1 answer:
slamgirl [31]4 years ago
7 0
A ratio is how many times one number can go into another for example 1:2 is a ratio so say you had 10 and 20 what is the ratio of ten to 20 it would 1:2 because 10 is half of 20 and half of 2 is one
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lukranit [14]

Answer:

Answer is in the attached image.

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2 years ago
To the nearest tenth the value of x that satisfies 2x = −2x + 11 is
olganol [36]

Answer:

2.8 (from 2.75 because of rounding)

Step-by-step explanation:

2x = -2x + 11

Add 2x on both sides

4x = 11

Divide 4 on both sides

x = 11/4

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3 years ago
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Estimate the perimeter and area of the figure to the nearest whole number. Please help!!
solniwko [45]

Answer:

29 ; 37

Step-by-step explanation:

The figure is composed by a square, a rectangle, and a right triangle

The perimeter of the square is 6 units

The perimeter of the rectangle is 10 units

The triangle is composed by a side of 6 units and a side of 5 units

The third side can be find with the Pythagorean theorem

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The total perimeter is

6 + 10 + 5 + 7,81025 = 28,81025 = 29

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2 years ago
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How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

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3 years ago
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KIM [24]
65 percent I check it
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