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skelet666 [1.2K]
3 years ago
12

Louis wants to carpet the rectangular floor of his basement. The basement has a area of 768 square feet. The width of the baseme

nt is 1/3 it’s length. What is the length of Louis’s basement
Mathematics
1 answer:
pentagon [3]3 years ago
5 0
Area=width*length. Let width=x ft, then length=3x ft, given the information in the problem. The area of basement=x*3x=768, 3x^2=768, x^2=256, x=16. The width is 16 feet. Therefore, length=3x=3*16=48 feet.
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Determine the selling price and amount of increase of a $450 painting with a 45% markup
melomori [17]

45% of 450 is 202.50

$202.50 is the price of markup

$652.50 is the selling price

8 0
4 years ago
Can (5z+3)(-5z-3) result in a difference of squares
castortr0y [4]

Answer:

no, it cannot

Step-by-step explanation:

a difference of square is: a² - b² = (a - b)(a + b)

looking at the expression (5z+3)(-5z-3), we see that it does not fit the criteria of the breakdown of a perfect square, as (-5z-3) has a negative <em>a</em> term (-5z)

if we FOILed (5z+3)(-5z-3) out, we would get:

-25z² - 30z - 9, which is not a difference of squares

8 0
3 years ago
X is number of 1$ bills 1/2x =20
SOVA2 [1]
If your trying to solve for x it’s 40, x=40
2 times 1/2x =2x20
x=2x20
x=40
4 0
4 years ago
Can someone actually help me with this
Komok [63]

Answer: X = 30*

All circles = 360*

we can subtract 260 from that because we know the length of one so we know the other is 130.

We are then left with only 100 and we know the two sides are equivalent so 100 / 2 = 50

6 0
3 years ago
A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the bod
adell [148]

Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A(t) = 10 (0.7)^t

To determine when 2mg is left in the body

We would have,

A(t) = 2, therefore

2 = 10(0.7)^t

0.7^t =2÷10

0.7^t = 0.2

Take the log of both sides,

Log (0.7)^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2/ 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A(t) = 1/2 A(0)

Thus,

1/2 A(0) = A(0)0.7^t

Divide both sides by A(0)

1/2 = 0.7^t

0.7^t = 0.5

Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours

6 0
3 years ago
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