In humans tongue rolling is dominant to the inability to tongue roll. If a heterozygous tongue roller and a non-tongue roller ha
ve a child, what are the chances the child will be a non-tongue roller?
1 answer:
Let's make the alleles Tt, where T is dominant (tongue rolling) and t is recessive (inability to tongue roll).
The heterozygous tongue roller would be Tt and the non tongue roller would be tt. Putting them in a punnet square (refer to attachment), the chances that their child will be a non tongue roller would be a 50% chance.
Tt: 2/4 = 50%
tt: 2/4 = 50%
The heterozygous tongue roller would be Tt and the non tongue roller would be tt. Putting them in a punnet square (refer to attachment), the chances that their child will be a non tongue roller would be a 50% chance.
Tt: 2/4 = 50%
tt: 2/4 = 50%
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