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ahrayia [7]
3 years ago
7

A rectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. The equation (x + 5)x = 104

represents the situation, where x represents the width of the rectangle.
The first step in solving by factoring is to write the equation in standard form, setting one side equal to zero. What is the equation for the situation, written in standard form?

x2 – 99 = 0
x2 – 99x = 0
x2 + 5x + 104 = 0
x2 + 5x – 104 = 0
Mathematics
2 answers:
____ [38]3 years ago
7 0

Answer:

x^2 + 5x - 104 = 0

Step-by-step explanation:

          (x + 5)x = 104         Original equation

        x^2 + 5x = 104         Distributive property

x^2 + 5x - 104 = 0             Subtract, make the right side equal to 0

choli [55]3 years ago
4 0

Answer:

D

Step-by-step explanation:

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Step-by-step explanation:

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John has 367 stamps And his uncle gave him some more stamps now he have 462 stamps how many stamps did he get from his uncle
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Step-by-step explanation:

7 0
3 years ago
NO LINKS!!!<br><br>Find the indicated side for each triangle below:​
pogonyaev

Problem 5

Apply the Law of Sines

s/sin(S) = r/sin(R)

s/sin(78) = 10/sin(48)

s = sin(78)*10/sin(48)

s = 13.162274

<h3>Answer:    13.162274 approximately</h3>

=============================================================

Problem 6

Use the Law of Sines here as well.

x/sin(X) = y/sin(Y)

x/sin(53) = 6/sin(22)

x = sin(53)*6/sin(22)

x = 12.791588

<h3>Answer:    12.791588 approximately</h3>
8 0
2 years ago
Read 2 more answers
4. Tom bought 333 pounds of
Lady_Fox [76]
Tom bought 768 pounds of candy because 333 + 435 = 768
8 0
2 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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