Select the best answer for the question.

Mathematics

2 answers:

irina1246 [14]3 years ago

7 0

The answer is supplementary

zvonat [6]3 years ago

6 0

They are supplementary because together they equal 180 B and D are vertical and so are A and C and they are also equal so the answer is D. Supplementary

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A spinner has 10 10 equal-sized sections. Six Six of the sections are purple purple. a. What is the probability that the spinne

borishaifa [10]

Answer:

P(Spinner lands on purple section) = 0.6 = 60%

Step-by-step explanation:

We are given the following in the question:

Number of sections = 10

Number of purple sections = 6

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

a) probability that the spinner will land on purple purple

P(purple) =

$=\dfrac{6}{10} = 0.6$

0.6 is the probability that the spinner will land on purple purple.

b) Interpretation of probability

$0.6\times 100\% = 60\%$

There is a 60% chance that the spinner will land on purple color.

7 0

2 years ago

What is the value of r+s+t when r = 26 , s= -12 , t= -8?

Len [333]

R + s + t

Plug in the values.
r = 26
s = -12
t = -8

r + s + t
26 + (-12) + (-8)
26 - 12 - 8
14 - 8
6

Remember these rules:

a + (+b) = a + b
a + (-b) = a - b
a - (+b) = a - b
a - (-b) = a + b

5 0

3 years ago

6. (4.2.12) Of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired. a. F

nata0808 [166]

Answer:

(a) Probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is 0.2711.

Step-by-step explanation:

We are given that of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired.

Let Probability that item are defective = P(D) = 0.20

Also, R = event of item being repaired

Probability of items being repaired from the given defective items = P(R/D) = 0.60

So, Probability of items not being repaired from the given defective items = P(R'/D) = 1 - P(R/D) = 1 - 0.60 = 0.40

(a) Probability that a randomly chosen item is defective and cannot be repaired = Probability of items being defective $\times$ Probability of items not being repaired from the given defective items