Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
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Answer:
Step-by-step explanation:
We can use the quadratic formula to get the answer to this
Quadratic Formula: -b +- √b² - 4ac/2a
Once we input A, B, and C into this, and solve any multiplication, we get
x = -1 +- √1 + 20/2
We divide by 2a, which 2a = 2.
-0.5 +- 10.5.
these are the following values of x:
x = 10
x = 11
Pretty sure this is it, hope it helps!
The area of one slice is roughly 14.13
The area of the whole pizza is 113.1
Divide that by 8
The product of -8. (-8)= 64