Why should the first digit in the quotient should be placed over the tens place of the dividend

Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim.

ArbitrLikvidat [17]

Answer:

a) There is not sufficient evidence to support the claim that the mean attendance is greater than 642.

Step-by-step explanation:

since in the question it is mentioned that the average attendance at games should be more 642 and according to this he moving the team with a larger stadium. Also the hypothesis conducted and the conclusion would be failure to deny the null hypothesis

So here the conclusion that should be made in non-technical term is that there should be no enough proof in order to support the claim that the mean attendence is more than $642

8 0

3 years ago

Plzzzzzzz help pppppppp

Pepsi [2]

Answer:

c

A

D

Step-by-step explanation:

i hope this helps

4 0

3 years ago

A recipe uses 5 cups of water for<br> every 3 cups of flour?

Lerok [7]

Answer:

There's no context for a conclusion.

Step-by-step explanation:

Comment when you've edited the question.

6 0

3 years ago

What is this answer -1/2 + 1/10

rewona [7]

Answer:

4536363646

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The personnel files of all eight employees at the Pawnee location of Acme Carpet Cleaners Inc. revealed that during the last six

irina [24]

Answer:

a) For Pawnee:

Range = 11, Mean = 3.13, Mean deviation = 2.44

For Chickpee:

Range = 7, Mean = 4.25, Mean deviation = 1.59

b) Pawnee Location has fewer lost days.

c) variation of the Chickpee is less than Pawnee location

Step-by-step explanation:

Data given:

For Pawnee:

3 1 0 0 2 11 5 3

Max = 11

Min = 0

Range = Max - Min

Range = 11-0 = 11

Range = 11

For Chickpee:

3 6 8 4 4 5 3 1

Max = 8

Min = 1

Range = Max - Min

Range = 8 - 1

Range = 7

For mean of Pawnee:

Mean = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3)/8

Mean = 25/8

Mean = 3.125

For mean deviation, we find the difference from the mean of each point.

Note: all the negative values will be taken as 0.

Differences from the mean of each point =

(3-3.13)=0.13, (1-3.31) = 2.13 ,

(0-3.13)=0, (0-3.13)=3.13,

(2-3.13)=1.13, (11-3.13)=7.87,

(5-3.13)=1.87, (3-3.13)=0.13

So, our differences are:

(0.13, 2.13, 0, 3.13, 1.13, 7.87, 1.87, 0.13 )

Mean deviation = Sum of all differences/8

Mean deviation = (0.13+2.13+3.13+3.13+ 1.13+ 7.87+ 1.87+ 0.13)/8

Mean deviation = 2.44

For mean of Chickpee:

Mean = (3+6+8+4+4+5+3+1)/8

Mean = 34/8

Mean = 4.25

Similarly, we need to find mean deviation for Chickpee, for that we need to find the differences first as done above for Pawnee.

Note: all the negative values will be taken as 0

Differences from the mean:

(3-4.25) = 1.25, (6-4.25) =1.75,

(8-4.25) = 3.75, (4-4.25)=0.25,

(4-4.25)=0.25, (5-4.25)= 0.75,

(3-4.25)=1.25, (1-4.25) =3.25

So, the differences are:

Differences = (1.25,1.75,3.75,0.25,0.25,0.75,1.25,3.25)

Mean deviation = (1.25+ 1.75+ 3.75+ 0.25+ 0.25+ 0.75+ 1.25+ 3.25)/8

Mean deviation = 1.59

b) which location has fewer lost days:

This can be found out by the total number of days of Pawnee and chickpee.

Pawnee = Sum of values = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3) = 25 days

Chickpee = Sum of values = (3+6+8+4+4+5+3+1) = 34 days

Hence, Pawnee Location has fewer lost days.

C) which location has less variation?

Formula for variation = ∑( $\frac{x^{2} }{8}$ ) - ( $mean^{2}$ )

where x = values of the set.

For Pawnee:

$mean^{2}$ = $3.13^{2}$ = 9.8

Sum of square of all the data points of Pawnee = 169

Variation = 169/8 - 98 = 11.325

Similarly,

For Chickpee:

$mean^{2}$ = $4.25^{2}$ = 18.06

Sum of square of all the data points of Chickpee = 176

Variation = 176/8 - 18.06

Variation = 22-18.06

Variation = 4

Hence, variation of the Chickpee is less than Pawnee location

8 0

3 years ago