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3 years ago

Hello Guys I am new hereWanna be my friend

Mathematics

2 answers:

slavikrds [6]3 years ago

8 0

hello!!!!!!!!!!!!!!!!!++

ValentinkaMS [17]3 years ago

8 0

Answer:

I think noo.. but joke hehe

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In a particular class, exams are worth 50% of the overall grade, quizzes are worth 30% of the overall grade, homework is worth 1

Paha777 [63]

Answer:

The student's overall grade is 85.79%

Step-by-step explanation:

Given in the question that:

Exam = 50%; Quiz = 30%, Home work = 15% and Class participation = 5%

The total giving us 100%.

A particular student scored the following;

87.9% on exams, 77.8% quiz, 90% Home work and 100% on class participation

Calculating the percentages the student had for each;

Exam total = 50*0.879 = 43.95% earned

Quiz = 30*0.778 = 23.34% earned

Home work = 15*0.9 = 13.5% earned

Class participation = 5*1 = 5% earned

Total earned = 43.95+ 23.34 + 13.5+ 5 = 85.79%

3 0

3 years ago

Michael has a set of 24 math problems to do for homework. Michael completed 1/4 of his homework in 3/4 of an hour. If he continu

gtnhenbr [62]

Given:

Total number of problems = 24

Michael completed $\dfrac{1}{4}$ of his homework in $\dfrac{3}{4}$ of an hour.

To find:

What fraction of his homework would he complete in one hour.

Solution:

We have,

Part of work done in $\dfrac{3}{4}$ of an hour $=\dfrac{1}{4}$

Part of work done in an hour $=\dfrac{4}{3}\times \dfrac{1}{4}$

$=\dfrac{1}{3}$

Therefore, he complete $\dfrac{1}{3}$ of his homework in 1 hour. Hence, all options are incorrect.

3 0

3 years ago

How do you find the value of a number

VikaD [51]

We calculate it by multiplying the place value and face value of the digit. For instance: If we consider a number 45. Here the digit 4 is in the tens column.

7 0

3 years ago

What's the mode and median for 22,36,9,27,30,20

zalisa [80]

Mode: none. All values occur once
Median 24.5

6 0

3 years ago

Distance between (-3,1) (1,5)

Mamont248 [21]

Answer & Step-by-step explanation:

For this problem, we will use the distance formula.

$d=\sqrt{(x2-x1)^2+(y2-y1)^2}$

For our (x1, y1), we will use (-3, 1). For our (x2, y2), we will use (1, 5). Now let's plug in our numbers and solve the problem.

$d=\sqrt{(1-(-3))^2+(5-1)^2}$

$d=\sqrt{4^2+4^2}$

$d=\sqrt{16 + 16}$

$d=\sqrt{32}$

$d=5.657$

So, the distance between (-3,1) and (1,5) is 5.657 units.

5 0

3 years ago

Hello Guys I am new hereWanna be my friend​

Hello Guys I am new hereWanna be my friend