The expression for the distance is w=5/3 ft
Step-by-step explanation:
The wall has a width of 16.5 feet
A single poster has a width of 5 3/4 ft which is equal to 23/4 ft or 5.75 ft
For the two posters, the width occupied is ; 23/4 * 2 = 23/2 = 11.5 ft
Remaining width that will be unoccupied by the posters will be 16.5-11.5=5
A sketch of the wall with the two posters such that the edge of the wall is the same as the distance between the posters will show three un-covered spaces, from edge of wall to the first poster, then between the two posters, and lastly from the second poster to the other edge of the wall.
The un-covered 3 portions have an equal width, lets assume that they have a width of w ft
This means 3w will represent the uncovered width which equals to the unoccupied space of 5 ft
Form equation for the uncovered width as;
3w=5ft
w=5/3 ft ---------the distance from the edge of each poster to the nearest edge of wall.
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Perimeter of a wall : brainly.com/question/12692838
Keyword :posters, wall, edge, distance
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