What is the distance between 3x - 5y + 3 =0 and 6x - 10y -12 =0
1 answer:
9514 1404 393
Answer:
(9/34)√34 ≈ 1.543
Step-by-step explanation:
The second equation can be rewritten as ...
6x -10y -12 = 0
3x -5y -6 = 0
3x -5y = 6
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The formula for the distance from point (x, y) to line ax+by+c=0 is ...
d = |ax+by+c|/√(a²+b²)
Then the distance from a point to the first line is ...
d = |3x -5y +3|/√(3² +(-5)²)
We know from the rearrangement of the second equation that points on its line satisfy (3x-5y) = 6. Substituting this value for (3x -5y) in the distance formula gives ...
d = |6 +3|/√34
Simplifying and rationalizing the denominator gives a distance of ...
d = (9/34)√34 ≈ 1.543
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Answer:
Step-by-step explanation:
We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).
Note that x=1 is a <em>vertical line </em>since x is 1 no matter what y is.
This means that if our new line is perpendicular to the old, then it must be a <em>horizontal line</em>.
So, since we have a horizontal line, then our equation must be our y-value of our point.
Our y-coordinate of our point (8,-9) is -9.
Therefore, our equation is:
And this is in standard form.
And we're done!