solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
14,28,42 and 56
Step-by-step explanation:
Multiply all lengths by 2 as the quadrilateral is dilated by a scale factor of 2
Answer:
y< 5/6 - 7
Step-by-step explanation:
First, you have to send 5x to the other side so youĺl -5x and the equation will be -6y>-5x+42
Then, you divide the equation on the left side by -6 because youll want y by itself. Remember, when you divide by a negative, you flip the greater than/equal to sign. itll now be y<-5/6 - 7
done
You would put 80 x
—- = ——
250 100
So those are fractions^
The first thing you do here is cross-multiply. (It doesn’t matter which sides you multiply together first)
So 250 times x= 250x
Then cross multiply 80 and 100 to get:
8,000
You now have ur new equation:
250x=8,000
The next thing you do here is divide both sides by 250, since 250 is the number with a variable in it (aka “x”)
You then get:
32 students as you’re final answer.
I hope that helped you understand !
