A building has two sizes of apartments, small and regular. The ratio of small

What condition on the probability distribution is necessary and sufficient in order that a limiting distribution exist, and what

Sholpan [36]

Answer:

The Markov chain is a description of the sequence of possible events in which the probability of an event depends only on the state attained in a previous separate event.

Step-by-step explanation:

The relation described by the Markov chain satisfies the following conditions:

1. All states communicate with themselves, that is P₁₁⁰ = 1 ≥ 0

2. There must be symmetry: if i←→j, then j ←→i

3. There must be transitivity. That is if i ←→k and k←→j, then i←→j

The conditions above imply that the communication is an example of an equivalence relation, meaning that it shares the properties with the more familiar relation, that is

i = i , if i = j ,then j = i etc

5 0

4 years ago

I have a couple of questions but this is just 1.

iVinArrow [24]

Domain is the x values
(x,y)
pick the beginning numbres

(1,0,2) is answer

8 0

3 years ago

Please help with only the circled ones (1-8)

mixas84 [53]

When you have an exponent divided by another exponent, you subtract the exponents (only when it has the same base)

For example:

$\frac{x^8}{x^3} =x^{8-3}=x^5$

$\frac{x^3}{x^2} =x^{3-2}=x^{1}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

$x^{-2}=\frac{1}{x^2}$

$\frac{1}{x^{-5}}=\frac{x^5}{1} = x^5$

$\frac{y^{-2}}{x^{-1}} =\frac{x^1}{y^2} =\frac{x}{y^2}$

1. $\frac{10^{15}}{10^3} =10^{15-3} = 10^{12}$

2. $\frac{(-3)^4}{(-3)^{-3}} =(-3)^{4-(-3)}=(-3)^{4+3} = (-3)^7$

3. $\frac{8}{8^3} =8^{1-3} = 8^{-2}=\frac{1}{8^2}$

4. $\frac{a^{12}}{a^2} =a^{12-2}=a^{10}$

5. $\frac{m^{-2}n^{16}}{m^{4}n^2} =(m^{-2-4})(n^{16-2})=(m^{-6})(n^{14})=\frac{n^{14}}{m^{6}}$

This is one of the ways you could have done it

6. $\frac{p^5q^{-10}}{p^6q^{-2}} =(p^{5-6})(q^{-10-(-2)})=(p^{-1})(q^{-8})=\frac{1}{p^1q^8} =\frac{1}{pq^8}$

7. $\frac{63x^{18}}{9x^{2} }$ Divide 63 and 9

$\frac{7x^{18}}{x^{2}} =(7)(x^{18-2})=(7)(x^{16})=7x^{16}$

8. $\frac{28r^4}{-7r^{15}} =(\frac{28}{-7} )(r^{4-15})=(-4)(r^{-11})=(-4)(\frac{1}{r^{11}} )=\frac{-4}{r^{11}}$

[More information with exponents]

If you multiply an exponent directly with another exponent, you multiply the exponents together

For example:

$(x^{2})^4=x^{2(4)}=x^8$

$(x^{3})^5 =x^{3(5)}=x^{15}$

If you multiply a variable with an exponent by a variable with an exponent, you add the exponents

For example:

$(x^{2}) (x^6)=x^{2+6}=x^8$

$(x^{3})(x^1)=x^{3+1}=x^4$

3 0

3 years ago

BRAINLIEST!!!!

vaieri [72.5K]

Answer: has a maximum

the maximum is 11

Step-by-step explanation:

f(x)= -5x^2-10x+6

the function f(x)= ax^2+bx+c=0 has a<0 so the equation has a maximum

I know V has the coordonate x=-b/2a, and y=-(b^2-4ac)/4a

b^2-4*a*c= (-10)^2-4*(-5)*6=100+120=220

so -b/2a=-(-10)/-2*5=+10/-10=-1 and

-(b^2-4ac)/4a=-220/4*(-5)=-220/-20=22/2=11

so V( -1, 11)

and the maximum is 11

4 0

3 years ago

WILL GIVE BRAINLIEST IF CORRECT

Ivahew [28]

Answer:

The second answer.

Step-by-step explanation:

Tim is correct. Absolute value is just the distance away from 0. In this case, both P and Q are 3/8 away from zero, even though they have opposite signs. In fact, opposites signs of the same number will always have the same absolute value because they are the same distance from 0.

So, it is the second one.

Hope this helps!

8 0

3 years ago

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