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katrin2010 [14]
3 years ago
9

Find the area. Simplify your answer.

Mathematics
2 answers:
irinina [24]3 years ago
8 0

Answer:

10x

Step-by-step explanation:

You just have to multiply 2x and 5 to get the area.

The answer is 10x.

Hope this helps!!

Let me know if I'm wrong!!

defon3 years ago
7 0
Answer: 10x. Area is length times width, so all you need to do is 5x times 2
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Write an equation and solve.<br> How opd am I if 400 reduced by 2 times my age is 244?
seropon [69]

Answer:

78

Step-by-step explanation:

x = your age

400 - 2x = 244

subtract 400 from both sides of the equation:

-2x = -156

divide both sides by -2:

x = 78

4 0
2 years ago
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A theater has 384 seats. Each row has 16 seats. What is the value of x in the area model?
yawa3891 [41]

Answer:

x=4

Step-by-step explanation: 64/16=4

3 0
2 years ago
Mrs. Reid is going on a trip. She has 9 book that she hasn't ready yet, but she wants to bring only 3 on the trip.
Karo-lina-s [1.5K]
The way you work this out is by thinking about the odds of each singular event, then finding the overall odds based on the individual odds.

The number of different books Mrs. Reid can choose is 9, so the first number is 9.

Mrs. Reid has picked one book so far, so now she has (1 - 9) = 8 books to choose from.
The of different books Mrs. Reid can choose now is 8, so your second number is 8.

Mrs. Reid has picked 2 book thus far, so now there are (2 - 9) = 7 books to choose from.
The of different books Mrs. Reid can choose now is 7, so your second number is 7.

To get the total number of different choices, multiply all the singular events together:

7*8*9=504\ different\ ways\ to\ bring\ 3\ books
7 0
3 years ago
(-2q^4)(-8q^3b^6)<br>help I need to simplify this problem
Montano1993 [528]
Multiply the constants. Multiply the variables according to the rules of exponents.
(-2q^{4})(-8q^{3}b^{6}) = ((-2)(-8))q^{(4+3)}b^{6}\\\\=16q^{7}b^6}
4 0
3 years ago
W^2+4w+4/2w^2-8<br> Simplify the expression
4vir4ik [10]
The answer would be
3w {}^{2}   + 4w - 8
hope I helped
7 0
3 years ago
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