Answer:
The 16 cans for 13.60
Step-by-step explanation:
21.36 ÷ 24 = 0.89
10.56 ÷ 12 = 0.88
17.20 ÷ 20 = 0.86
13.60 ÷ 16 = 0.85
The 16 cans for 13.60 is the best buy, just remember, cost ÷ amount!!
Per round there are a certain amount of teams which cuts the amount of games in half. For Example, in the first round there are 64 teams which cuts the amount of games in half to 32 games. This will keep occurring until there are only 2 teams left with one game (This declares the winner).
First round:
64 teams
32 games
Second round:
32 teams
16 games
Third round:
16 teams
8 games
Fourth Round:
8 teams
4 games
Fifth Round:
4 teams
2 games
Sixth Round:
2 teams
1 game
___________
Thus, a winner will be determined in the sixth round of the tournament.
___________
Best of Luck!
If you have 2 functions, f(x) and g(x), you would find f(g(x)) and g(f(x)). If, after you simplify both and you end up with just "x" as the answer, they are inverses of each other. For example, f(x) = 3x - 2 and g(x) = (x+2)/3
f(g(x)) takes the g function and plugs it into the x in the f function, like this:
![f(g(x))=3[ \frac{(x+2)}{3} ]-2](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D3%5B%20%5Cfrac%7B%28x%2B2%29%7D%7B3%7D%20%5D-2%20)
cancel out the 3's to get
f(g(x))=(x+2)-2 which is just x. Now do it the other way: g(f(x))
![g(f(x))= \frac{[(3x-2)+2]}{3}](https://tex.z-dn.net/?f=g%28f%28x%29%29%3D%20%5Cfrac%7B%5B%283x-2%29%2B2%5D%7D%7B3%7D%20)
3x-2+2 is 3x, so we have

See?
Hey there! The topic for this problem is Limit of Function!
As for the question, we are given the quadratic function and we have to find the limit, the value that approaches to a.

We call this, "The limit of f(x) when x approaches a."
Then you may ask, "How do we find the limit of function?". That is a very nice question! The answer to your problem is <u>j</u><u>u</u><u>s</u><u>t</u><u> </u><u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>e</u><u> </u><u>x</u><u>-</u><u>v</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>i</u><u>n</u><u>.</u> Although this substitution method only applies when the approaching value doesn't make the denominator to 0. I believe that in the beginning of Limit topic, we learn how to find or evaluate the basic limit that only requires substitution.
So from the question, we receive:

Next step is to <u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>e</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>2</u> in the function.

Evaluate the value.

Cancel the limit out and there you have it!

Answer
- The limit of quadratic function when x approaches 2 is -3.
Now whenever you learn limit, you must know that limit is when we substitute the <u>a</u><u>p</u><u>p</u><u>r</u><u>o</u><u>a</u><u>c</u><u>h</u><u>i</u><u>n</u><u>g</u><u> </u><u>v</u><u>a</u><u>l</u><u>u</u><u>e</u><u>.</u> That means x —> 2 is not x = 2 but x approaches 2.
Regarding the limit, any questions and doubts can be asked through comment and I will get back to you soon!
Thank you for using Brainly and I hope you have a fantastic day! Good luck on the assignment.
<span>x+5y=8 ----------------- (1)
</span>y=3x ----------------- (2)
Substitute (2) into (1):
x + 5(3x) = 8
Distribute 5:
x + 15x = 8
Combine like terms:
16x = 8
Divide both sides by 16:
x = 0.5
Substitute x = 0.5 into (2):
y = 3(0.5)
Distribute 3
y = 1.5
Answer: x = 0.5, y = 1.5