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Sphinxa [80]
3 years ago
7

14. In a game, Theodore received a handful of coins (pennies, nickels, dimes, and quarters) as a prize. When he got home, he fou

nd that he had managed to get $2.09 in change. He noticed that he had three times as many pennies as dimes, one more nickel than dimes, and twice as many quarters as dimes. How many quarters did Theodore get in his prize? F. 4 G. 5 H. 6 J. 7 K. 8 0​
Mathematics
1 answer:
quester [9]3 years ago
3 0

Answer:

Step-by-step explanation:

.

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The relationship between time and distance remaining on a 3 mile walk for someone walking at a rate of 2miles per hour
Maksim231197 [3]

Answer:

Remaining\ distance=3-2t\ \ \ \ \ \ \ \ \ (where\ t\ is\ time)

Step-by-step explanation:

Total\ distance=3\ mile\\\\speed=2\ miles/hour\\\\Time=t\\\\In\ t\ hours\ distance\ covered=velocity\times time=2\times t=2t\\\\Remaining\ distance=total\ distance-distance\ covered\\\\Remaining\ distance=3-2t

6 0
3 years ago
A locker combination has three nonzero digits and digits cannot be replaced. The first two digits are 9 and 8. What is the proba
Deffense [45]

Answer:

1 in 7

Step-by-step explanation:

Your one-digit choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

But they're nonzero, so: 1, 2, 3, 4, 5, 6, 7, 8, 9.

But they can't be repeated and 9 and 8 are used, so: 1, 2, 3, 4, 5, 6, 7.

Only 7 numbers left, so chances are, 1 in 7.

8 0
3 years ago
Find the multiplicative inverse of 6 + 2i
Marina CMI [18]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2774989

________________


Find the multiplicative inverse of

\mathsf{z=6+2i}

________


The inverse multiplicative of  \mathsf{z=a+bi}  is

\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\
=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}

=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\
\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}

________


For this question,

\mathsf{z=6+2i}


So,

\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{6+2i}}\\\\\\
=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\
=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\
=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}


\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

6 0
3 years ago
Read 2 more answers
a sugar solution was made by mixing 8 qt of a 2% sugar solution and 6 qt. of a 51% sugar solution. find the concentration of the
melisa1 [442]
<span>16 + 306 = 1400x
322 = 1400x
x = 322/1400
</span><span>x = 0.23 = 23% (That is the concentration of the mixture)</span><span>Equation:
sugar + sugar = sugar
0.02*8 + 0.51*6 = x(8+6)

Multiply thru by 100 to get:
-----
2*8 + 51*6 = 1400x
</span>
3 0
2 years ago
H what is the name of the sequence below
skad [1K]
3, 6 ,9, 12, 15

I think it should be 3 then add 3
7 0
3 years ago
Read 2 more answers
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