Answer:
(2,8)
Step-by-step explanation:
Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
Answer:
g(4)=10
Step-by-step explanation:
576 I hope this help cause I did this two years ago so I'm a little rusty but I think this is correct
Given:
hours parking charge
4 5.50
7 7.75
7 - 4 = 3 hours
7.75 - 5.50 = 2.25
2.25 / 3 = 0.75
0.75 is the change in amount for every hour spent. It is the variable unit rate
4 hours is 5.50.
Cost of parking for 3 hours is: 5.50 - 0.75 = 4.75
0.75 x 4 hours = 3
5.50 - 3 = 2.5 fixed charge.
total parking charge: y = 2.50 + 0.75x
