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2 years ago

5

A piece of paper can be made into a cylinder in two ways : by joining the short sides together, or by joining the long sides tog

ether which cylinder holds more, how much more?

1 answer:

julia-pushkina [17]2 years ago

3 0

They hold the same amount i think

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tim has been offered three jobs. job a paid on an annual basis with a salary of 26,700. job b pays $500 per week. job c pays &am

scZoUnD [109]

Answer:

Job C

Step-by-step explanation:

Since he's paid semi monthly,literally half a month, which is 1125$

Then full month will be 1125×2

Which is 2250

Then annually would be 2250×12=27,000

5 0

2 years ago

Is it possible for a number to be a rational number that is not an interger but is a whole number. Explain

mylen [45]

Whole numbers are a subset of integers, which in turn are a subset of rational numbers.

So, every whole number is an integer, and every integer is a rational number.

So, it is possible for a rational number not to be an integer. Think of any decimal number: 1.356 is a rational number, but it's not an integer.

On the other hand, if a number is not an integer, it can't be a whole number, because all whole numbers are integers.

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2 years ago

I need your help guys! :)

nadya68 [22]

Emmmm derecha izquierda 56 a la cuadrada de 4 triangulada sobre17 raíz 12

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2 years ago

A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat

Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect population,

$\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100$

$\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100$

$\text{Growth percentage}=\frac{\text{10}}{20} \cdot100$

$\text{Growth percentage}=0.5 \cdot100=50$

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

$P(w)=20(1+0.50)^{w}$ , where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

$P(11)=20(1+0.50)^{11}$

$P(11)=20(1.50)^{11}$

$P(11)=20\cdot 86.49755859375$

$P(11)=1729.951171875\approx 1730$

Therefore, population of insects at the end of 11th week will be 1730.

7 0

3 years ago

Use the arc length formula to find the length of the curve y = 2 − x2 , 0 ≤ x ≤ 1. Check your answer by noting that the curve is

Lina20 [59]

By using the arc length formula, we will see that the length of the curve is L = 1.48

<h3>How to use the arc length formula?</h3>

Here we have the curve:

y = 2 - x^2 with 0 ≤ x ≤ 1

And we want to find the length of the curve.

The arc length formula for a curve y in the interval [x₁, x₂] is given by:

$L =\int\limits^{x_2}_{x_1} {\sqrt{1 + \frac{dy}{dx}^2} } } \, dx$

For our curve, we have:

dy/dx = -2x

And the interval is [0, 1]

Replacing that we get:

$L =\int\limits^{1}_{0} {\sqrt{1 + (-2x)^2} } } \, dx\\\\L \int\limits^{1}_{0} {\sqrt{1 + 4x^2} } } \, dx\\$

This integral is not trivial, using a table you can see that this is equal to:

$L = (\frac{Arsinh(2x)}{4} + \frac{x*\sqrt{4x^2 + 1} }{2})$

evaluated from x = 1 to x = 0, when we do that, we will get:

$L = \frac{Arsinh(2) + 2*\sqrt{5} }{4} = 1.48$

That is the length of the curve.

If you want to learn more about curve length, you can read:

brainly.com/question/2005046

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1 year ago