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3 years ago

Factor and Solve. Show work.

Mathematics

1 answer:

Naddik [55]3 years ago

4 0

Step-by-step explanation:

1. We we can split 4p into 9p - 5p, and now we have 3p² + 9p - 5p - 15 = 0. We can take out 3p from the first 2 terms and -5 from the last 2 terms. This gets us 3p (p + 3) -5 (p + 3) = 0. These two terms have (p + 3) as a common facor, so we can take that out as well, which give us (p + 3)(3p - 5) = ). Using Zero Product Property, p + 3 = 0 and 3p - 5 = 0, and when we solve each equation, we get p = -3, p= 5/3.

2. We will use the same process.

6x² + 14x - 3x - 7 = 0

2x (3x+7) - 1 (3x+7) = 0

(3x + 7)(2x - 1) = 0

3x + 7 = 0, 2x - 1 = 0

x = -7/3, x=1/2

Hope this helps!

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3 years ago

Read 2 more answers

What is the following quotient? 5/√11-√3

kati45 [8]

ANSWER

$\frac{5( \sqrt{11} + \sqrt{3} )} {8}$

EXPLANATION

The given rational function is

$\frac{5}{ \sqrt{11} - \sqrt{3}}$

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

$\sqrt{11} - \sqrt{3}$

which is

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When we rationalize we obtain:

$\frac{5( \sqrt{11} + \sqrt{3} )}{(\sqrt{11} - \sqrt{3} )( \sqrt{11} + \sqrt{3} )}$

The denominator is now a difference of two squares:

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We apply this property to get

$\frac{5( \sqrt{11} + \sqrt{3} )}{( \sqrt{11}) ^{2} - ( \sqrt{3}) ^{2} )}$

$\frac{5( \sqrt{11} + \sqrt{3} )}{11 - 3}$

This simplifies to

$\frac{5( \sqrt{11} + \sqrt{3} )} {8}$

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3 years ago

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while observing the fare meter in a taxi, a student records the following data: reading on taxi fare meter time (minutes) meter

mario62 [17]

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y = mx + b
(0,5.25)...x = 0 and y = 5.25
slope(m) = 0.85
now we sub, we r looking for b, the y int
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