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pishuonlain [190]
3 years ago
14

Factor and Solve. Show work.

Mathematics
1 answer:
Naddik [55]3 years ago
4 0

Step-by-step explanation:

1. We we can split 4p into 9p - 5p, and now we have 3p² + 9p - 5p - 15 = 0. We can take out 3p from the first 2 terms and -5 from the last 2 terms. This gets us 3p (p + 3) -5 (p + 3) = 0. These two terms have (p + 3) as a common facor, so we can take that out as well, which give us (p + 3)(3p - 5) = ). Using Zero Product Property, p + 3 = 0 and 3p - 5 = 0, and when we solve each equation, we get p = -3, p= 5/3.

2. We will use the same process.

6x² + 14x - 3x - 7 = 0

2x (3x+7) - 1 (3x+7) = 0

(3x + 7)(2x - 1) = 0

3x + 7 = 0, 2x - 1 = 0

x = -7/3, x=1/2

Hope this helps!

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How do I get this answer?
Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

  • cos(2x) = cos²(x) -sin²(x)
  • cos²(x) +sin²(x) = 1
  • cos(x) = 1/sec(x)

<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

  2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}

4 0
2 years ago
If Andrew can paint 1 house in 4 days, which sentence is true? A. Andrew can paint 9 houses in 27 days. B. Andrew can paint 8 ho
mezya [45]

Answer:

The answer is C.

Step-by-step explanation:

I got this by multiplying the houses by the days it would take to paint to paint one house.

9*4=27

8 0
3 years ago
Read 2 more answers
If you flip a coin 4 times, what is the best prediction possible for the number of times it will land on tails?
allochka39001 [22]

Answer:

2

Step-by-step explanation:

Each time you flip a coin, there is a 50% change of it landing on tails.  So half the time you should get a tails.  

Half of 4 is 2, so you will likely get 2 tails.

7 0
3 years ago
The number of girls in Mrs. Manning’s classes was 12 less than twice the number of boys. She had a total of 108 students in her
FromTheMoon [43]

40 boys and 68 girls

let's start with variables and an equation.

boys: x

girls: 2x - 12

and we know that boys and girls make up the class. so let's add the two expressions.

x + 2x - 12 = 108

3x - 12 = 108

    + 12     + 12

3x = 120

x = 40 boys

BUT x is only the number of BOYS in the class. so we have to find girls now. let's plug in our value of x into the girls' equation.

2x - 12 = # of girls

2(40) -12 = # of girls

80 - 12 = # of girls

68 girls

let's check our answer!

68 + 40 does in fact add to 108, therefore our answer is correct.

4 0
3 years ago
Please help! Create a set of five positive numbers (repeats allowed) that have a median of 10 and a mean of 14. What thought pro
Brilliant_brown [7]
Alright, since there are 5 numbers, and the mean (or average) is (sum)/(amount of numbers), we have (sum)/5=14. Multiplying both sides by 5, we have the sum being 80. The median of 10 means that in a, b, c, d, e, 10 has to be c and the numbers have to be in ascending order. A and b must be 10 or lower, while d and e must be 10 or higher. Putting some random numbers in, we can have 1, 1, 10, 15, and e. We left e there because the sum needs to be 80, and since 1+1+10+15=27, 80-27=53=e. This, however, would not work if e was less than 10 and we therefore would have needed to make some numbers lower to compensate for this. Our answer is therefore 1, 1, 10, 15, 53
6 0
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