Please help #10 its unit rates.

Suppose a card is drawn at random from a standard deck. The card is then shuffled back into the deck. Then for a second time a c

Oduvanchick [21]

Answer:

Probability = 0.0288

Step-by-step explanation:

For the first draw.

There are total of 52 cards in a deck of cards and a total of 26 red cards in a deck of cards.

Probability of drawing a red= 26/52

Probability = 0.5

For the second draw. Actually the initial card drawn was replaced. Total number of face cards are 12.

Probability of drawing a face card = 12/52= 0.23076923

For the third draw .

There are 13 diamond cards in total.

Probability of a diamond = 13/52

Probability = 0.25

Probability of red,face, diamond= 0.5*0.23076923*0.25=0.028846

To four decimal place = 0.0288

6 0

3 years ago

F(x)=5^x if F(-2) what does this equal

KengaRu [80]

Answer:

$\frac{1}{25}$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ = $\frac{1}{a^{m} }$ , hence

f(- 2) = $5^{-2}$ = $\frac{1}{5^{2} }$ = $\frac{1}{25}$

3 0

3 years ago

Can someone please help me with this problem?

Shkiper50 [21]

Answer: E

Step-by-step explanation: I’d say this because if they are intersecting that means that it would most likely make a perpendicular line

8 0

3 years ago

The local store where Tim shops charges a 7% sales tax for clothing. Complete the table by figuring the cost of the jeans after

Sindrei [870]

Answer:

$A=P+P\times S\%$

Step-by-step explanation:

For calculating the sales tax of a product, it is required to first multiply the original cost price of the product by the sales tax percentage.

Once the sales tax has been computed add it to the original cost price in order to determine the total cost of the product.

The formula of final amount is:

$A=P+P\times S\%$

Here,

A = final amount

P = original cost price

S = sales tax percentage

7 0

3 years ago

Please I beg you help me

Elena L [17]

Answer:

Option D

Step-by-step explanation:

Going through the choices will help determine which option best simulates the random selection of a voter.

Flip a coin three times, and assign outcomes as follows: HHH, HHT, or HTH = Nava; HTT, THH, or THT = Jensen; TTH = Moretti, TTT = Chang.

Given that it is a random selection of the 4 candidates, it means the probability of choosing either one of them is equivalent. From the option, it can be found that Nava and Jensen have a higher chance of being voted than Moretti and Chang, which would not fit the criteria of being randomly selected.

Roll a number cube, and assign outcomes as follows: 1 or 2 = Nava, 3 or 4 = Jensen, 5 = Moretti, 6 = Chang.

Again, Nava and Jensen have a higher chance of being voted than Moretti and Chang. Therefore, this is not the correct option to simulate random selections of the 4 candidates.

Roll a number cube, and assign outcomes as follows: 1, 2, or 3 = Nava, 4 = Jensen, 5 = Moretti, 6 = Chang.

Nava has a higher chance of being voted, so this option does not fit the stimulation.

Flip a coin twice, and assign outcomes as follows: HH = Nava, HT = Jensen, TH = Moretti, TT = Chang

In this scenario, all 4 candidates have an equal chance of being voted, so this option would best simulate the random selection of a voter from the city.

Hope this helps :)

8 0

3 years ago