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ElenaW [278]
1 year ago
11

Solve (5√16)^1 using prime factorisation.​

Mathematics
1 answer:
krok68 [10]1 year ago
7 0

Answer:

2^{\frac{4}{5}}

Step-by-step explanation:

Factor 16 using prime factorisation:

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

⇒ 16 = 2⁴

Substitute 16  for  2⁴:

\implies (\sqrt[5]{16})^1=(\sqrt[5]{2^4})^1

\textsf{Apply exponent rule}\quad \sqrt[n]{a^b} =a^{\frac{b}{n}}:

\implies (\sqrt[5]{2^4})^1=(2^{\frac{4}{5}})^1

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies (2^{\frac{4}{5}})^1=2^{\frac{4}{5}}

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Marrrta [24]

Answer:

the answer is y =3/4 or alternate form y = 0.6

6 0
3 years ago
If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree)
Naddik [55]

Answer:

57.5 degrees

Step-by-step explanation:

Assuming this is a triangle

a is adjacent is ∠B

b is opposite of ∠B

Use the inverse tangent equation: tan^{-1} (11/7)

This equals to 57.52880771

3 0
3 years ago
1. What is the center and radius of the circle?<br> (x-4)² + (x-7) ² - 49
tester [92]

Answer:

Center at (4, 7) and radius is √49, or 7

Step-by-step explanation:

Didn't you mean (x-4)² + (y-7) ² = 49?

Comparing          (x-4)² + (y-7) ² = 49

to                          (x - h)^2 + (y - k)^2 = r^2, we see that the center is at (h, k)  =>  (4, 7) and that the radius is √49, or 7.

4 0
3 years ago
A rectangular swimming pool measures 50 meters in length and 25 meters in width. If the length in the scale drawing is 10 cm, wh
mash [69]

Answer:

The 25 m width of the actual swimming pool in the scale drawing is 5 cm

Step-by-step explanation:

The dimensions of the actual swimming pool given are

Length = 50 meters

Width = 25 meters

The length of the swimming pool on the scale drawing = 10 cm

The scale of the scale drawing is therefore;

10 cm on the scale drawing is equivalent to 50 meters of the actual swimming pool

Which gives;

10 cm:50 m

However, 50 m = 5,000 cm, therefore;

10 cm:5,000 cm or 10 : 5,000

Which is 10 to 5000 or 10/10 to 5000/10 = 1 to 500

The scale of the scale drawing is 1 to 500

or 1 cm of the scale drawing = 5 meters of the actual swimming pool

Therefore, the width of 25 meters of the actual swimming pool can be given as follows;

5 m = 1 cm

1 m = 1 cm/5

25 m = 25× 1 m = 25 × 1 cm/5 = 5 cm

Therefore, the 25 m width of the actual swimming pool in the scale drawing = 5 cm.

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3 years ago
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