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Ierofanga [76]
3 years ago
10

What is the inverse of the given equation y=7x^2-3?

Mathematics
1 answer:
NARA [144]3 years ago
5 0

Answer:

The inverse of this equation would be y = \sqrt{\frac{x - 3}{7} }

Step-by-step explanation:

To find the inverse of any equation, start by switching the y and x values. Then solve for the new y value. That equation will be your inverse.

y = 7x^2 - 3

x = 7y^2 - 3

x + 3 = 7y^2

\frac{x-3}{7} = y^2

\sqrt{\frac{x - 3}{7} } = y

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<em />

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