What is the inverse of the given equation y=7x^2-3?

Mathematics

1 answer:

NARA [144]3 years ago

5 0

Answer:

The inverse of this equation would be y = $\sqrt{\frac{x - 3}{7} }$

Step-by-step explanation:

To find the inverse of any equation, start by switching the y and x values. Then solve for the new y value. That equation will be your inverse.

y = 7x^2 - 3

x = 7y^2 - 3

x + 3 = 7y^2

$\frac{x-3}{7}$ = y^2

$\sqrt{\frac{x - 3}{7} }$ = y

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