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vfiekz [6]
3 years ago
14

What is the least common multiple of 8 10 and 12

Mathematics
2 answers:
leonid [27]3 years ago
7 0
LCM\ is\ the\ least\ common\ number\ that\ is\ multiply\ of\ each:\\\\ 
Factors\ of\ 8:\\8:2\\4:2\\2:2\\\\ 
Factors\ of\ 10:\\ 10:2\\5:5\\\\Factors\ of\ 12:\\ 12:2\\6:2\\3:3\\\\ 
LCM(8,10,12)=2^3*3*5=120

Nastasia [14]3 years ago
7 0
It's 2.
because 8 and 12 can be divided by 4 equally but not 10.
2 I'd the only number that goes into 8,10 and 12 equally.
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Mrs. Write makes cookies for the school bake sale. She uses the equation y=0.50x to determine the cost, y, for x cookies. Which
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Answer:D

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3 0
3 years ago
Dan factored x^2+121 into (x+1-11)
babunello [35]

Answer:

Your question is a little unclear.  If you are just trying to factor x² + 121, it's prime.  (can't be factored using real numbers).

Step-by-step explanation:

The difference of two squares is a special form.  a² - b² = (a+b)(a-b).  

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4 years ago
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4 0
4 years ago
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What is the value of x?<br> 11 (9 - 2x) = -(12x + 11)
fenix001 [56]
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3 0
3 years ago
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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

A=P(1+r)^x

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

1000=P(1+r)^0\implies P = 1000

A = 1900 when x = 1,

1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9

Thus, the required function that represents the population after x days,

A=1900(1+0.9)^x=1900(1.9)^x

If x = 4,

The number of mosquito after 4 days,

A=1900(1.9)^4 = 24760.99\approx 24761

If A = 60,000,

60000 = 1900(1.9)^x

\frac{600}{19}=1.9^x

Taking log both sides,

\log(\frac{600}{19})=x\log 1.9

\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4

Thus, there will 60,000 mosquitoes after 5 days.

6 0
3 years ago
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