First, find the probability of each event:
1) the probability that the spinner will land on a 7.
Since the spinner is split 4 equal sections and there is only 1 sector with 7, we can say the probability of getting a 7 is 1/4 as there is only 1 of 7 out of the total of 4 sections.
<em>and</em>
2) the probability that the spinner will land on B.
Since the spinner is split into 3 equal sections, and there is only 1 sector for B, we can say the probability of getting B is 1/3.
To find the probability of 2 events, we need to multiply the two probabilities.
1/4*1/3 = 1/12
So the answer is 1/12.
You must find the relative rates of both workers...
T=f/3 and J=f/2 so if they work together to clear the field then:
ft/3+ft/2=f make all terms have a common denominator of 6
(2/2)(ft/3)+(3/3)(ft/2)=(6/6)f
2ft/6+3ft/6=6f/6 multiply both sides by 6
2ft+3ft=6f divide both sides by f
2t+3t=6 combine like terms on left side
5t=6 divide both sides by 5
t=6/5 hr
t=1 1/5 hr
t=1 hr 12 min
To build the table you just have to give values to t and then calculate the corresponding c a per the model.
If the model is c = 5.5 t this is the table
t c
5.5 t
0 5.5(0) = 0
1 5.5(1) = 5.5
2 5.5(2) = 11.0
3 5.5(3) = 16.5
4 5.5(4) = 22.0
5 5.5(5) = 27.5
The viables solutions are all where t is equal or greater than 0. You can even use decimal values for t. You cannot use negative values for t.
Let the function be y = ax + c.
For (-1,8), 8 = a(-1) + c → 8 = - a + c
For (5,6), 6 = a(5) + c → 6 = 5a + c
Subtract one from abother,
2 = - 6a => - 1/3 = a
Hence, 8 = - 1/3 + c → 23/3 = c
Relation is:
y = (-1/3)x + (23/3)
3y = - x + 23
3y = 23 - x
Substitute -1 for the variable x.
f(-1) = 2(-1) - 2
f(-1) = -2 - 2
f(-1) = -4
