123 rounded to the nearest hundred is 100 i believe
Answer:
<u>TO FIND :-</u>
- Length of all missing sides.
<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>
<u>SOLUTION :-</u>
1) θ = 16°
Length of side opposite to θ = 7
Hypotenuse = x


≈ 25.3
2) θ = 29°
Length of side opposite to θ = 6
Hypotenuse = x


≈ 12.3
3) θ = 30°
Length of side opposite to θ = x
Hypotenuse = 11


4) θ = 43°
Length of side adjacent to θ = x
Hypotenuse = 12


≈ 8.8
5) θ = 55°
Length of side adjacent to θ = x
Hypotenuse = 6


≈ 3.4
6) θ = 73°
Length of side adjacent to θ = 8
Hypotenuse = x


≈ 27.3
7) θ = 69°
Length of side opposite to θ = 12
Length of side adjacent to θ = x


≈ 4.6
8) θ = 20°
Length of side opposite to θ = 11
Length of side adjacent to θ = x


≈ 30.2
9514 1404 393
Answer:
a) ∆RLG ~ ∆NCP; SF: 3/2 (smaller to larger)
b) no; different angles
Step-by-step explanation:
a) The triangles will be similar if their angles are congruent. The scale factor will be the ratio of any side to its corresponding side.
The third angle in ∆RLG is 180° -79° -67° = 34°. So, the two angles 34° and 67° in ∆RLG match the corresponding angles in ∆NCP. The triangles are similar by the AA postulate.
Working clockwise around each figure, the sequence of angles from lower left is 34°, 79°, 67°. So, we can write the similarity statement by naming the vertices in the same order: ∆RLG ~ ∆NCP.
The scale factor relating the second triangle to the first is ...
NC/RL = 45/30 = 3/2
__
b) In order for the angles of one triangle to be congruent to the angles of the other triangle, at least one member of a list of two of the angles must match for the two triangles. Neither of the numbers 57°, 85° match either of the numbers 38°, 54°, so we know the two triangles have different angle measures. They cannot be similar.
Answer:
75%
Step-by-step explanation:
Convert the fraction into a decimal number. Multiply the obtained decimal number by 100, to get a percent value.